我需要使用bootstrap模式上传图像文件。但似乎遇到了这样的错误
我不知道还能做什么。有人能帮我吗?
HTML观看次数
<div class="modal fade" id="modal_add_new_supplier_product" tabindex="-1" role="dialog">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title">New product form</h4>
</div>
<div class="modal-body">
<form class="form-horizontal" enctype="multipart/form-data" accept-charset="utf-8" id="form_add_newproduct" method="post" action="">
<div class="form-group row">
<div class="col-lg-4 col-md-4 col-sm-4">Product image</div>
<div class="col-lg-8 col-md-8 col-sm-8">
<input type="file" name="product_image" id="product_image" />
<span id="product_image_status" class="label label-danger"></span>
</div>
</div>
</form>
</div>
<div class="modal-footer">
<button data-dismiss="modal" class="btn btn-default">No</button>
<button type="button" class="btn btn-success btn-sm" onclick="uploadImage()">Insert new product</button>
</div>
</div>
</div>
</div>
要上传的剧本
function uploadImage() {
// send the image_data
var image_data = $('#product_image').prop('files')[0];
$.ajax({
type:'POST',
url : '<?php echo site_url('suppliers/upload_image') ?>',
data:image_data,
cache:false,
contentType: false,
processData: false,
success : function(data) {
console.log(data);
$('#modal_add_new_supplier_product').modal('hide');
$('body').removeClass('modal-open');
$('.modal-backdrop').remove();
$('#modal_add_new_supplier_product').on('hidden.bs.modal',function(){
// window.location.reload();
})
}
});
}
控制器:
public function upload_image()
{
echo json_encode($this->input->post()).'<br/>';
$image_path = realpath(APPPATH . '../images');
echo $image_path.'<br/>';
$config = array(
'upload_path' => $image_path,
'upload_url' => base_url()."/images/",
'allowed_types' => "gif|jpg|png|jpeg",
'overwrite' => TRUE,
'max_size' => "2000KB",
'max_height' => "768",
'max_width' => "1024"
);
$this->load->library('upload', $config);
if($this->upload->do_upload())
{
echo 'success';
}else
{
print_r( $this->upload->display_errors());
}
}