我原以为Try
捕获了跨线程异常,如下例所示。我猜不是:那么如何在衍生的子线程中捕获异常?
// Simple class that throws error
class Child extends Runnable {
def run {
val exception: Exception = new Exception("Foo")
val i = 1
Thread.sleep(1000)
val lines = scala.io.Source.fromFile("/tmp/filefoobar.txt").mkString
Thread.sleep(1000)
}
}
// spawn the class above
def Parent() = {
val doit = Try {
val t = new Thread(new Child)
t.start
t.join()
}
doit match {
case Success(v) => println("uh oh did not capture error")
case Failure(v) => println("good we caught the error")
}
}
输出 阶>父()
Exception in thread "Thread-35" java.io.FileNotFoundException: /tmp/filefoobar.txt (No such file or directory)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(FileInputStream.java:195)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at scala.io.Source$.fromFile(Source.scala:91)
at scala.io.Source$.fromFile(Source.scala:76)
at scala.io.Source$.fromFile(Source.scala:54)
at $line120.$read$$iw$$iw$Child.run(<console>:16)
at java.lang.Thread.run(Thread.java:745)
uh oh did not capture error
答案 0 :(得分:3)
考虑使用Futures来处理异步任务的结果
import ExecutionContext.Implicits.global
val resultFuture: Future[Unit] = Future { new Child.run }
resultFuture.onComplete (result: Try[Unit] => ...)
答案 1 :(得分:0)
当子进程访问该文件时会引发异常,该异常捕获JRE并遵循默认行为;打印堆栈跟踪,然后将异常传播到父进程,这会捕获您在输出中看到的Parent。
你可以做的是在子进程中捕获异常并抛出异常,以便父进程可以处理它。
答案 2 :(得分:0)
您可以使用Thread.setUncaughtExceptionHandler
设置例外,然后从try:
import java.lang.Thread.UncaughtExceptionHandler
def Parent() = {
@volatile
var maybeException: Option[Throwable] = None
val doit = Try {
val target = new Child
val t = new Thread(target)
t.setUncaughtExceptionHandler(new UncaughtExceptionHandler {
override def uncaughtException(t: Thread, th: Throwable): Unit = {
maybeException = Some(th)
}
})
t.start()
t.join()
maybeException.foreach(th => throw th)
}
doit match {
case Success(v) => println("uh oh did not capture error")
case Failure(v) => println("good we caught the error")
}
}