Question

我使用swift，我得到了这个功能。

func spawnTwo（） - ＆gt; SKSpriteNode {

    let two = SKSpriteNode(imageNamed: "landPic1")
    two.anchorPoint = CGPoint(x: 0.5, y: 0.5)
    two.name = "Obs"
    two.zPosition = 5;
    two.anchorPoint = CGPoint(x: 0.5 , y: 0.5);
    two.position.x = 0
    two.position.y = 0

    self.scene?.addChild(two)


    return two

}

现在我想，每当我调用该函数时，1280都会添加position.x。我该怎么做？

Answer 1

只需将变量保留在函数之外：

var n = 0
func spawnTwo() -> SKSpriteNode {

    //...
}

在函数中，您将1280乘以n并增加n：

let two = SKSpriteNode(imageNamed: "landPic1")
two.anchorPoint = CGPoint(x: 0.5, y: 0.5)
two.name = "\(n)bs" // you might want to change the name each time too
two.zPosition = 5;
two.anchorPoint = CGPoint(x: 0.5 , y: 0.5);
two.position.x = 1280 * n
two.position.y = 0

self.scene?.addChild(two)
n += 1

return two

调用函数后改变位置

1 个答案: