Question

我的字符串是：

var str = "hi {0} your contact is {1}";

{0}，{1}表示我们可以替换为该字符串的动态数据。必须找到＆＃34; {0}＆＃34;并将其替换为数组中包含的对象：

var my_arr=[[{"data":"priya"},{"data":"reena"},{"data":"mathew"}],[{"data":"123456"},{"data":"745896"},{"data":"236521"}]]

我希望用my_arr [0]数据替换{0}，用my_arr [1]数据替换{1}。最后我的输出将是这样的：

var result={"hi priya your contact is 123456","hi reena your contact is 745896","hi mathew your contact is 236521"}.

请帮我这样做，数组格式的任何更改都是可以接受的。提前谢谢。

Answer 1

尝试以下代码。

＆＃13;

var str = "hi {0} your contact is {1}";

var my_arr=[[{"data":"priya"},{"data":"reena"},{"data":"mathew"}],[{"data":"123456"},{"data":"745896"},{"data":"236521"}]]

var result = [];

$.each(my_arr[0],function(i) {
  var str = "hi {0} your contact is {1}";
  result.push(str.replace('{0}',my_arr[0][i].data).replace('{1}',my_arr[1][i].data));
});
console.log(result);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

Answer 2

像这样使用nested loop和string replace

＆＃13;

var my_arr=[[{"data":"priya"},{"data":"reena"},{"data":"mathew"}],[{"data":"123456"},{"data":"745896"},{"data":"236521"}],[{"data":"address1"},{"data":"address2"},{"data":"address3"}]]

var str = "hi {0} your contact is {1}  and address is {2}";
var new_arr =[];
	 
for(i=0;i<my_arr.length;i++)
 {
     for(j=0;j<my_arr[i].length;j++)
     {
        if(i==0)
	{  
            str_1 = str.replace("{"+i+"}",my_arr[i][j]['data']);
            new_arr.push(str_1);
         }
	else
	{
	    new_arr[j]=new_arr[j].replace("{"+i+"}",my_arr[i][j]['data']); 
        }
     }		 
  }
	
console.log(new_arr);

＆＃13;

查找和替换字符串中的字符与数组对象动态jquery

2 个答案: