Gimp,python-fu:runtimeError:pdb.gimp_image_merge_down中的执行错误

时间:2017-05-05 19:41:16

标签: python ubuntu gimp python-fu gimpfu

我的目标是将一个图像放在另一个图像上,并将生成的图像保存为jpeg文件。 第一个是新的,它有450x300尺寸和白色背景。第二个是从文件加载的,其可见部分作为图层添加到第一个。

我已将以下python脚本添加到 /usr/lib/gimp/2.0/plug-ins 文件夹

#!/usr/bin/python
import os

from gimpfu import *
import gimpfu

import logging
def scale(timg, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    timg = pdb.gimp_file_load(imageName, imageName)

    tdraw = pdb.gimp_layer_new_from_visible(timg, newImage, 'logo')      
    newImage.add_layer(tdraw, 1)
    finalLayer = pdb.gimp_image_merge_down(newImage,tdraw,1)
    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, finalLayer, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)

通过

运行
gimp --no-interface -b '(python-fu-my RUN-NONINTERACTIVE 0 0 "logo.png")' -b '(gimp-quit 0)'

返回

  

(gimp:4224):GLib-CRITICAL **:g_error_new_literal:断言'域名   != 0'失败回溯(最近一次呼叫最后):文件   “/usr/lib/gimp/2.0/python/gimpfu.py”,第821行,在_run返回   apply(func,params [1:])File“/usr/lib/gimp/2.0/plug-ins/my.py”,   第31行,在规模finalLayer =   pdb.gimp_image_merge_down(newImage,tdraw,1)RuntimeError:执行   错误批处理命令遇到执行错误:错误:(:1)   执行python-fu-my失败的程序

有什么问题?如何正确地理解并解决问题的根本原因。

编辑。 以下是xenoid的建议: 1)使用 gimp_image_merge_down 会产生 logo.jpeg ,白色背景为450,300尺寸

def my(timg, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    # pdb.gimp_context_set_foreground((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    logger.info('loading logo {0}'.format(imageName))
    logo = pdb.gimp_file_load(imageName, imageName)
    # logoDrawable = pdb.gimp_image_get_active_layer(logo)

    #
    visibleLayer = pdb.gimp_layer_new_from_visible(logo, newImage, 'logo')
    newImage.add_layer(visibleLayer, 1)
    mergedL = pdb.gimp_image_merge_down(newImage, newLayer, 0)

    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, mergedL, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)

2)使用 newImage.add_layer(visibleLayer,0)导致原始 png 图像作为以 jpg 格式存储的输入

def scale(logo, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    # pdb.gimp_context_set_foreground((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    logger.info('loading logo {0}'.format(imageName))
    logo = pdb.gimp_file_load(imageName, imageName)
    # logoDrawable = pdb.gimp_image_get_active_layer(logo)

    #
    visibleLayer = pdb.gimp_layer_new_from_visible(logo, newImage, 'logo')
    newImage.add_layer(visibleLayer, 0)
    # mergedL = pdb.gimp_image_merge_down(newImage, newLayer, 0)

    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, visibleLayer, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)

1 个答案:

答案 0 :(得分:1)

此:

tdraw = pdb.gimp_layer_new_from_visible(timg, newImage, 'logo')      
newImage.add_layer(tdraw, 1)

不会将图层添加为顶层,而是添加现有顶层。如果它是第二层,那么它就成了底层。在这种情况下,merge_down无法合并。