我想通过不键入每个div
(#TopicA
,#TopicB
,#main
等)ID来简化代码。被选中。
除了触发按钮的自动崩溃之外,我希望所有divs
。我怎样才能做到这一点?
示例:当我点击TopicA1
时,我想要折叠所有其他div
,但我不想将所有div
ID放在JS代码中。
演示:JSFiddle
<div id="main" class="QA">
<h2>Title</h2>
<h3>Subtitle</h3>
<button class="ClassButtonA">Topic A</button>
<button class="ClassButtonB">Topic B</button>
<button class="ClassButtonC">Topic C</button>
</div>
<div id="TopicA" class="QA">
<h2>XX</h2>
<button class="ClassButtonA1">Topic A1</button>
</div>
$(".ClassButtonA").click(function() {
$("#TopicA").toggle("slow").trigger('reset');
});
$(".ClassButtonA").click(function() {
$("#TopicB, #TopicC, #main").slideUp("slow").trigger("reset");
答案 0 :(得分:1)
单个函数处理切换,并将所有兄弟节点隐藏到当前显示的div。请注意,我确实修改了一些结构 - 内容窗格div现在包含我希望显示/隐藏的所有div,从而显示按钮窗格。希望它有所帮助!
// Event handler for click on any button el
$(".QA button").click(function() {
// The text of the button matches the id
// of the div els, if I strip spaces.
var toggleThis = "#" + $(this).text().replace(/\s/g, '')
// Using the given string above, toggle that
// div el, and hide all siblings to that.
$(toggleThis).show("slow").trigger('reset').siblings().hide("slow").trigger('reset');
});
&#13;
.QA {
font: normal normal 14px/1 Helvetica;
margin: 1px;
border-radius: 10px;
text-align: center;
}
#TopicA,
#TopicB,
#TopicC,
#TopicA1 {
display: none;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="main" class="QA">
<h2>Title</h2>
<h3>Subtitle</h3>
<button class="ClassButtonA">Topic A</button>
<button class="ClassButtonB">Topic B</button>
<button class="ClassButtonC">Topic C</button>
</div>
<div class="content-pane">
<div id="TopicA" class="QA">
<h2>XX</h2>
<button class="ClassButtonA1">Topic A1</button>
</div>
<div id="TopicA1" class="QA">
<h2>123</h2>
</div>
<div id="TopicB" class="QA">
<h2>YY</h2>
</div>
<div id="TopicC" class="QA">
<h2>ZZ</h2>
</div>
</div>
&#13;