我想知道我该怎么办?将< script type = "text/javascript" >
var seriesOptions = [],
seriesCounter = 0,
names = {
{
ticker
}
};
/**
* Create the chart when all data is loaded
* @returns {undefined}
*/
function createChart() {
Highcharts.stockChart('chart_container', {
rangeSelector: {
selected: 2
},
yAxis: {
labels: {
formatter: function() {
return (this.value > 0 ? ' + ' : '') + this.value + '%';
}
},
plotLines: [{
value: 0,
width: 2,
color: 'silver'
}]
},
plotOptions: {
series: {
compare: 'percent',
showInNavigator: true
}
},
tooltip: {
pointFormat: '<span style="color:{series.color}">{series.name}</span>: <b>{point.y}</b> ({point.change}%)<br/>',
valueDecimals: 2,
split: true
},
series: seriesOptions
});
}
$.each(names, function(i, name) {
seriesOptions[i] = {
name: name,
data: pricerec# from python
};
// As we're loading the data asynchronously, we don't know what order it will arrive. So
// we keep a counter and create the chart when all the data is loaded.
seriesCounter += 1;
if (seriesCounter === names.length) {
createChart();
}
});
< /script>
与template<typename T>
一起使用?
typedef
我正在尝试对模板类型的项目进行排序。
template <typename T>
typedef bool (*cmp_func)(T i0, T i1); // <- syntax error here
答案 0 :(得分:2)
Typedef不能是模板。但是,C ++ 11 using
别名可以是:
template <typename T>
using cmp_func = bool (*)(T i0, T i1);
pre-C ++ 11解决方法是创建一个具有type
typedef的模板结构:
template <typename T>
struct cmp_func {
typedef bool (*type)(T i0, T i1);
};
然后将其引用为typename cmp_func<int>::type
。