Question

我在java中使用tapestry，我在tml文件中有一个循环，每行都有一个按钮。单击按钮时，我需要将行中元素的值传递给onSuccess（）方法。我用t：context =＆＃34; value＆＃34;尝试了它。在按钮中，但它不起作用，我找不到解决方案。

TML：

<tr t:type="Loop" t:source="movieList" t:value="movie">
    <td>
        <a href="#" t:type="PageLink" t:page="index">
            ${movie.title}
        </a>
    </td>
    <td>
        ${movie.score}
    </td>
    <td>
        <form t:type="Form" class="form-horizontal" t:id="deleteMovie">
            <button type="submit" t:context="movie.movieId" class="btn btn-primary">
                <img src="${context:i/basura.png}" width="25" heigth="25"/>
            </button>
        </form>
    </td>
</tr>

Java方法：

 @OnEvent(value = "success", component ="deleteMovie")
 Object[] onSuccesFromDeleteMovie(Long movieId) throws InstanceNotFoundException {
     movieService.removeMovie(movieId);
     return new Object[] {startIndex};
 }

Answer 1

It "doesn't work" because your button is a plain HTML button, not a Tapestry component. In this case t:context will be rendered as a plain HTML attribute, you can verify that by inspecting resulted HTML.

To let Tapestry know that your button is actually a Tapestry Submit component, you can add the t: prefix to the type attribute, i.e.:

<button t:type="submit" t:context="movie.movieId" ... />

Foreseeing your next question: returning Object[] from an event handler won't work because it's not a supported method return value.

对于这样一个简单的用例，您可以在上下文中使用普通EventLink，您不必提交表单来触发服务器端事件处理程序。

如果您决定在某个时候使用Ajax，也许这个JumpStart's AjaxFormLoop example会有所帮助。

将值传递给方法onSucces

1 个答案: