当您点击给定的Azure功能端点时,我想从Blob存储中返回一个文件。这个文件是二进制数据。
根据Azure存储Blob文档,最相关的调用似乎如下,因为它是唯一一个不需要将文件写入临时文件的调用:
getBlobToStream
然而,此调用获取Blob并将其写入流。
Azure Functions是否有办法将Stream用作res.body的值,以便我可以从存储中获取Blob内容并立即将其写入响应?
要添加一些代码,尝试使用这样的代码:
'use strict';
const azure = require('azure-storage'),
stream = require('stream');
const BLOB_CONTAINER = 'DeContainer';
module.exports = function(context){
var file = context.bindingData.file;
var blobService = azure.createBlobService();
var outputStream = new stream.Writable();
blobService.getBlobToStream(BLOB_CONTAINER, file, outputStream, function(error, serverBlob) {
if(error) {
FileNotFound(context);
} else {
context.res = {
status: 200,
headers: {
},
isRaw: true,
body : outputStream
};
context.done();
}
});
}
function FileNotFound(context){
context.res = {
status: 404,
headers: {
"Content-Type" : "application/json"
},
body : { "Message" : "No esta aqui!."}
};
context.done();
}
答案 0 :(得分:6)
不幸的是,我们还没有在NodeJS中实现流媒体支持 - 它位于积压工作中:https://github.com/Azure/azure-webjobs-sdk-script/issues/1361
如果您没有打开使用C#函数的NodeJ,则可以直接在输入绑定和流请求输出中使用存储sdk对象,而不是使用中间对象方法。
答案 1 :(得分:3)
虽然@Matt Manson的回答基于我提出问题的方式肯定是正确的,但以下代码段对于遇到这个问题的人来说可能更有用。
虽然我无法直接将Stream发送到响应主体,但我可以使用自定义流将数据捕获到Uint8Array中,然后将其发送到响应主体。
注意:如果文件非常大,这将占用大量内存。
'use strict';
const azure = require('azure-storage'),
stream = require('stream');
const BLOB_CONTAINER = 'deContainer';
module.exports = function(context){
var file = context.bindingData.file;
var blobService = azure.createBlobService();
var outputStream = new stream.Writable();
outputStream.contents = new Uint8Array(0);//Initialize contents.
//Override the write to store the value to our "contents"
outputStream._write = function (chunk, encoding, done) {
var curChunk = new Uint8Array(chunk);
var tmp = new Uint8Array(this.contents.byteLength + curChunk.byteLength);
tmp.set(this.contents, 0);
tmp.set(curChunk, this.contents.byteLength);
this.contents = tmp;
done();
};
blobService.getBlobToStream(BLOB_CONTAINER, file, outputStream, function(error, serverBlob) {
if(error) {
FileNotFound(context);
} else {
context.res = {
status: 200,
headers: {
},
isRaw: true,
body : outputStream.contents
};
context.done();
}
});//*/
}
function FileNotFound(context){
context.res = {
status: 404,
headers: {
"Content-Type" : "application/json"
},
body : { "Message" : "No esta aqui!"}
};
context.done();
}
答案 2 :(得分:0)
我从上面的最后一条评论中尝试了@Doug的解决方案,在我的azure函数中添加了一些次要的mod,到目前为止,在尝试了20种不同的想法之后,这是唯一实际将文件交付给浏览器的想法!谢谢@Doug ...
const fs = require("fs");
const stream = require("stream");
...
const AzureBlob = require('@[my_private_artifact]/azure-blob-storage');
const azureStorage = new AzureBlob(params.connectionString);
//Override the write to store the value to our "contents" <-- Doug's solution
var outputStream = new stream.Writable();
outputStream.contents = new Uint8Array(0);//Initialize contents.
outputStream._write = function (chunk, encoding, done) {
var curChunk = new Uint8Array(chunk);
var tmp = new Uint8Array(this.contents.byteLength + curChunk.byteLength);
tmp.set(this.contents, 0);
tmp.set(curChunk, this.contents.byteLength);
this.contents = tmp;
done();
};
let azureSpeedResult = await azureStorage.downloadBlobToStream(params.containerName, params.objectId, outputStream);
let headers = {
"Content-Length": azureSpeedResult.size,
"Content-Type": mimeType
};
if (params.action == "download") {
headers["Content-Disposition"] = "attachment; filename=" + params.fileName;
}
context.res = {
status: 200,
headers: headers,
isRaw: true,
body: outputStream.contents
};
context.done();
...