C ++调车码算法和表达式树实现

时间:2017-05-05 07:06:34

标签: c++ algorithm

我是C ++的新手,并使用调车场算法来构建表达式树。我已经坚持了几天这个问题。我试图获取根节点的值但它失败了。

中缀输入

(1+2)*(3/4)-(5+6)

以下代码是基于shungting码的功能:

vector<string> infixToRPN(vector<string> tokens) {
    vector<string> output;
    stack<string> stack;
    string o1;
    string o2;
    //traverse tokens
    for (int i = 0; i < tokens.size(); ++i) {

        // if token is operator
        if (isOperator(tokens[i])) {
            string o1 = tokens[i];
            if (!stack.empty()) {
                string o2 = stack.top();
                while (isOperator(o2) && comparePrecendence(o1, o2) <= 0) {
                    // pop off o2 and on to the output;
                    stack.pop();
                    output.push_back(o2);
                    if (!stack.empty())
                        o2 = stack.top();
                    else
                        break;
                }

            }
            //push o1 on to the stack;
            stack.push(o1);

        }
        //if token is left bracket
        else if (tokens[i] == "(") {
            stack.push(tokens[i]);
        }
        //if token is right bracket
        else if (tokens[i] == ")") {
            string topToken = stack.top();
            while (stack.top() != "(") {
                output.push_back(topToken);
                stack.pop();
                if (stack.empty()) break;
                topToken = stack.top();
            }
            if (!stack.empty()) stack.pop();

        }
        // if token is number and add it to ouput;
        else
        {
            output.push_back(tokens[i]);
        }
    }
    //pop the rest of token
    while (!stack.empty()) {
        string restToken = stack.top();
        output.push_back(restToken);
        stack.pop();
    }
    return output;
}

测试结果表明解析器似乎正常工作:

12+34/*56+-

所以我猜错误可能发生在我的buildTree函数中。在buiilding之后,getRoot()函数返回的值总是与正确的值不一致。在我的情况下,根应该是“ - ”,而我得到一个“0”。

 ExprTree ExprTree::buildTree(vector<string> tokens){
    ExprTree t ;
    TreeNode * n, * n1, * n2;
    TreeNode * r = t.getRoot();
    vector<string> postfix = infixToRPN(tokens);
    stack<TreeNode *> stack;
    for (int i = 0; i < postfix.size(); ++i) {
        //if number


        if (!isOperator(postfix[i])) {
            n = createOperatorNode(postfix[i]);
            stack.push(n);
        }
        else // if operator
        {   
            n= createOperatorNode(postfix[i]);
            if (!stack.empty())
                t = ExprTree(stack.top());
            // pop two tree nodes 
            n1 = stack.top();
            stack.pop();
            n2 = stack.top();
            stack.pop();
            //set children nodes;
            n->setLeftChild(n2);
            n->setRightChild(n1);

            stack.push(n);

        }

    }

    return t;
}

0 个答案:

没有答案