Question

我有以下数组，长度和值都是动态的

$one = array('11','12');
$two = array('0','0','0','0','1','1');

想要结果

$result = array('11','11','11','11','12','12');

Answer 1

foreach ($two as $key => $value)
{
    $result[$key] = $one[$value];
}

Answer 2

我们正在使用array_map，array_unique和preg_replace来表达所需的输出。

Try this code snippet here

<?php
$one = array('11','12');
$two = array('0','0','0','0','1','1');

$search=array_map(function($value){
    return $value='/\b'.$value."\b/";
},array_unique($two)); //Here we are creating an array which we want to search

print_r(preg_replace($search, $one, $two));

<强>输出：

Array
(
    [0] => 11
    [1] => 11
    [2] => 11
    [3] => 11
    [4] => 12
    [5] => 12
)

Answer 3

我这样做：

<?php
$one = array('11','12');
$two = array('0','0','0','0','1','1');

$result = array();
foreach($two as $i){
    $result[] = $one[(int) $i];
}

print_r($result);
?>

Answer 4

Sahil的回答太低效了。使用更少的代码可以更有效地实现所需的输出。

输入：

$one = array('11','12');
$two = array('0','0','0','0','1','1');

方法＃1：array_map()

$result=array_map(function($v)use($one){return $one[$v];},$two));
var_export($result);

方法＃2：array_walk()

array_walk($two,function($v)use($one,&$result){$result[]=$one[$v];});
var_export($result);

方法＃3：foreach()

foreach($two as $v){
    $result[]=$one[$v];
}
var_export($result);

输出（无论方法如何）：

array (
  0 => '11',
  1 => '11',
  2 => '11',
  3 => '11',
  4 => '12',
  5 => '12',
)

我该如何动态替换数组值

4 个答案: