Spring Boot + Security + JWT无法生成令牌

时间:2017-05-05 03:29:44

标签: java spring-boot spring-security jwt

我使用JWT配置了弹簧启动和安全性,一切都运行了一段时间。

这是我的webSecurityConfig

httpSecurity
            .csrf().disable()
            .exceptionHandling().authenticationEntryPoint(unauthorizedHandler).and()
            .sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).and()
            .authorizeRequests()
            .antMatchers(HttpMethod.POST, "/user/cadastrar/**").permitAll()
            .antMatchers(HttpMethod.POST, "/auth/**").permitAll()
            .anyRequest().authenticated();
    httpSecurity
            .addFilterBefore(authenticationTokenFilterBean(), UsernamePasswordAuthenticationFilter.class);
    httpSecurity.headers().cacheControl();

第一条路线" / users / cadastrar"工作正常。

问题是我的第二条路线" / auth" 使用用户名和密码在主体上调用/ auth它将在我的JwtAuthenticationTokenFilter类中放置此函数

protected void doFilterInternal(HttpServletRequest request, HttpServletResponse response, FilterChain chain) throws ServletException, IOException {
    String authToken = request.getHeader(this.tokenHeader);
    String username = jwtTokenUtil.getUsernameFromToken(authToken);
    logger.info("checking authentication for user " + username);
    if (username != null && SecurityContextHolder.getContext().getAuthentication() == null) {
        UserDetails userDetails = this.userDetailsService.loadUserByUsername(username);
        if (jwtTokenUtil.validateToken(authToken, userDetails)) {
            UsernamePasswordAuthenticationToken authentication = new UsernamePasswordAuthenticationToken(userDetails, null, userDetails.getAuthorities());
            authentication.setDetails(new WebAuthenticationDetailsSource().buildDetails(request));
            logger.info("authenticated user " + username + ", setting security context");
            SecurityContextHolder.getContext().setAuthentication(authentication);
        }
    }
    chain.doFilter(request, response);
}

然后它将转到我的AuthenticationController类并运行此函数

@RequestMapping(value = "${jwt.route.authentication.path}", method = RequestMethod.POST)
public ResponseEntity<?> createAuthenticationToken(@RequestBody JwtAuthenticationRequest authenticationRequest, Device device) throws AuthenticationException {

    // Perform the security
    final Authentication authentication = authenticationManager.authenticate(
            new UsernamePasswordAuthenticationToken(
                    authenticationRequest.getUsername(),
                    authenticationRequest.getPassword()
            )
    );
    SecurityContextHolder.getContext().setAuthentication(authentication);

    // Reload password post-security so we can generate token
    final UserDetails userDetails = userDetailsService.loadUserByUsername(authenticationRequest.getUsername());
    final String token = jwtTokenUtil.generateToken(userDetails, device);

    // Return the token
    return ResponseEntity.ok(new JwtAuthenticationResponse(token));
}

问题似乎是代码的这个特定部分:

// Perform the security
    final Authentication authentication = authenticationManager.authenticate(
            new UsernamePasswordAuthenticationToken(
                    authenticationRequest.getUsername(),
                    authenticationRequest.getPassword()
            )
    );

当它试图返回对象&#34; UserNamePasswordAuthenticationToken&#34;它只是将断点发送到函数的末尾&#34; doFilterInternal&#34;特别是在&#34; chain.doFilter&#34;之后的括号。调用

1 个答案:

答案 0 :(得分:0)

问题解决了!显然连续编码16小时会影响你的想法!

上面的代码没有任何问题,出于某种原因我默认设置了我新创建的用户!