Question

出于某种原因，每当我在代码中输入一种设定颜色时，它就会给我一个错误。任何人都可以看到这里的问题

这是我的app类：

import javax.swing.JOptionPane;
public class binCollectionAPP{
    public static void main(String[] args){
        //Declare Variables
        int apartmentNum, flag;
        String collect, binColour;

        //Objects
        binCollection bin = new binCollection();

        //Inputs
        apartmentNum=Integer.parseInt(JOptionPane.showInputDialog("Enter your apartment number"));
        binColour=JOptionPane.showInputDialog("Enter the colour bin you are checking");

        //set
        bin.setApartNum(apartmentNum);
        bin.setBinColour(binColour);

        //compute
        bin.compute();

        //get
        collect=bin.getCollectDay();
        flag=bin.getFlag();

        //output
        if(flag == 1){
            JOptionPane.showMessageDialog(null,"Error, incorrect bin colour");
        }
        else if(flag == 2){
            JOptionPane.showMessageDialog(null,"Error, incorrect apartment number");
        }
        else{
            JOptionPane.showMessageDialog(null,"Your collection day is "+collect);
        }

    }
}

我的可实例化课程是：

public class binCollection{
    //Declare Vars
    private int apartmentNum, flag;
    private String collect, binColour;

    //Constructor
    public binCollection(){
        apartmentNum = 0;
        flag = 0;
        collect = "";
        binColour = "";
    }

    //set methods
    public void setApartNum(int apartmentNum){
        this.apartmentNum = apartmentNum;
    }
    public void setBinColour(String binColour){
        this.binColour = binColour;
    }

    //compute
    public void compute(){
        if(apartmentNum % 2 == 0){
            if(binColour == "brown" || binColour == "Brown" ){
                collect = "Monday";
            }
            else if(binColour == "black"){
                collect = "Tuesday";
            }
            else if(binColour == "green"){
                collect = "Wednesday";
            }
            else{
                flag = 1;
            }
        }
        else if(apartmentNum % 2 == 1){
            if(binColour == "brown"){
                collect = "Tuesday";
            }
            else if(binColour == "black"){
                collect = "Wednesday";
            }
            else if(binColour == "green"){
                collect = "Thursday";
            }
            else{
                flag = 1;
            }
        }
        else{
            flag = 2;
        }
    }

    //get methods
    public String getCollectDay(){
        return collect;
    }
    public int getFlag(){
        return flag;
    }
}

我哪里错了？

关于错误：我没有收到编译器错误，它全部编译并运行但在运行时输入公寓号和颜色＆＃34;棕色＆＃34;，然后我收到错误（代码中的标志2）

对于＆＃34;输入您的公寓号码＆＃34;我输入2，对于颜色，我尝试过黑色和棕色。全部收到相同的错误

Answer 1

您的问题在于如何检查颜色。在Java中，使用import ast with open('C:\\Users\\Moondra\Anaconda_related\Jupyer_notebooks\MachineLearning\Small_cap_Bio.txt', 'r') as f: my_list = ast.literal_eval(f.read())方法完成字符串相等性（使用.equals()，String检查物理相等性，这不是您想要的。改变你的条件

==

或者，为了更加简单，请尝试使用if (binColour.equals("brown") || binColour.equals("Brown")) { collect = "Monday"; }

.equalsIgnoreCase()

输出无效，收到错误

1 个答案: