Python IMAP4不要将消息标记为已读

时间:2017-05-04 19:56:52

标签: python imap

我有一个Python脚本来移动具有特定主题的邮件。消息被标记为已读,我不希望它们被标记为已读。脚本的哪一部分将它们标记为已读,如何使其不标记为已阅读?

另外,我不太清楚我在做什么,所以如果有任何多余的代码或错误,请告诉我。

import getpass
from Crypto.Hash import MD5
import sys
import imaplib
import email
import re

password = getpass.getpass()
match = "redacted"

username  = "redacted"
dest = "000"
pattern_uid = re.compile('\d+ \(UID (?P<uid>\d+)\)')

def md5(message):
    hash = MD5.new()
    hash.update(message)
    return hash.hexdigest()

md5 = md5(password)

if md5 == match:
    pass
else:
    print "Mismatch"
    sys.exit()

M = imaplib.IMAP4_SSL("mail.redacted.com", 993)
M.login(username, password)
M.select()
typ, data = M.search(None, 'ALL')
M.select('Inbox')

msgs = M.search(None, 'ALL')[1]
num_messages = len(msgs[0].split())
num_messages += 1


def parse_uid(data):
    match = pattern_uid.match(data)
    return match.group('uid')

for i in range(1, num_messages):
    try:
        typ, msg_data = M.fetch(str(i), '(RFC822)')
    except:
        pass
    for response_part in msg_data:
        if isinstance(response_part, tuple):
            UID = M.fetch(str(i),'UID')
            UID = UID[1]
            try:
                UID = parse_uid(UID[0])
            except:
                pass
            msg = email.message_from_string(response_part[1])
            for header in [ 'subject'  ]:
                if msg[header] == "Redacted":
                    result = M.uid('COPY', UID, dest)
                    if result[0] == 'OK':
                        mov, data = M.uid('STORE', UID, '+FLAGS', '(\Deleted)')
                        M.expunge()


M.close()
M.logout()

1 个答案:

答案 0 :(得分:1)

typ, msg_data = M.fetch(str(i), '(RFC822)')

获取邮件正文将其标记为已读。您将要使用BODY.PEEK[]

虽然,我不知道你为什么要提取整条信息只是为了复制它。为什么不提取标题?使用BODY.PEEK[HEADERS]