Question

我有一个复杂的查询，提供如下输出。

Name Date       Value1 Value2
D    1493803432  12    14
S    1493803432  20    22
T    1493803432  24    42
D    1493803424  20    15
S    1493803424  30    23
T    1493803424  65    42
D    1493804556  22    11
S    1493804556  45    23
T    1493804556  55    24

我想要的输出是将行添加为两行或更多行的总和。和按日期分组字段，示例如下。

Name Date    Value1   Value2
D    1493803432  12    14
S    1493803432  20    22
T    1493803432  24    42
TS   1493803432  44    64
D    1493803424  20    15
S    1493803424  30    23
T    1493803424  65    42
TS   1493803424  95    65
D    1493804556  22    11
S    1493804556  45    23
T    1493804556  55    24
TS   1493804556  100   57

我可以做联合但不能按日期分组。所以TS是T＆amp; S的总和，不包括D和个别日期字段。

Answer 1

我想你可以试试这个：

SELECT NAME, DATE, VALUE1, VALUE2 
FROM <your complex query>
UNION ALL
SELECT 'TS' AS NAME, DATE, SUM(VALUE1) AS VALUE1, SUM(VALUE2) AS VALUE2
FROM <your complex query> 
WHERE NAME IN ('T','S')
GROUP BY DATE
ORDER BY DATE, NAME

Answer 2

您可以使用如下查询：

onSubscribe

查询使用条件聚合，以便对每个组中仅 publish(Function)，SELECT Name, Date, Value1, Value2, 1 AS grp FROM mytable UNION ALL SELECT 'TS' AS Name, Date, SUM(CASE WHEN Name IN ('T', 'S') THEN Value1 ELSE 0 END) AS Value1, SUM(CASE WHEN Name IN ('T', 'S') THEN Value2 ELSE 0 END) AS Value2, 2 AS grp FROM mytable GROUP BY Date, grp ORDER BY Date, grp个记录求和。字段'T'是'S'子句使用的数字文字，用于实现所需的输出。

Demo here

Answer 3

尝试

SELECT name,
       date_col,
       TO_NUMBER (value1),
       TO_NUMBER (value2)
  FROM my_table2
UNION
  SELECT 'TS' name,
         (date_col),
         SUM (CASE WHEN name IN ('T', 'S') THEN value1 ELSE '0' END) value1,
         SUM (CASE WHEN name IN ('T', 'S') THEN value2 ELSE '0' END) value2
    FROM my_table2
GROUP BY date_col
ORDER BY date_col, name

在sql查询中将所选行聚合为total和group by datetime

3 个答案: