Question

使用laravel eloquent选择特定的字段值。但是，我发现自己正在处理这个错误

SQLSTATE [HY000]：常规错误：1366不正确的整数值：'[{“id”：1}]'用于第1行的'department_id'列（SQL：插入`opportunity`（`category`，`机会） `，`vacancies`，`department_id`，`updated_at`，`created_at`）值（Attachement，Assistant，2，[{“id”：1}]，2017-05-04 02：12：04，2017-05 -04 02:12:04））

department_id的字段值应该是int，它从另一个表中绘制，如下所示

public function store(Request $request)
{
   // return $request->all();

         $this->validate($request,[
        'department'=>'required',
        'category'=>'required',
        'description'=>'required|string',
        'positions'=>'required|integer',
        ]);
    //dd($request); table('departments')->where('dep_name', '$dep')
     $dep = $request->department;
     $department=Department::all();
     //dd($department);

     $department_id = Department::select('id')->where('dep_name','=', $dep)->get();

    // return $department_id;

     $newOpportunity = Opportunity::create(
        [
            'category'=>$request->category,
            'opportunity'=>$request->description,
            'vacancies'=>$request->positions,
            'department_id'=>$department_id,
        ]
        );
     $newOpportunity ->save();

    return redirect('admin/');  
}

Answer 1

将数组作为值传递给derpartment_id列。 Id位于您需要像这样访问它的数组中

'department_id'=>$department_id[0]->id,

Answer 2

声明

Department::select('id')->where('dep_name','=', $dep)->get();

返回Collection。

您需要单个记录的id。试试这个

$department = Department::where('dep_name','=', $dep)->first();

if($department != null) {
     $newOpportunity = Opportunity::create(
        [
            'category'=>$request->category,
            'opportunity'=>$request->description,
            'vacancies'=>$request->positions,
            'department_id'=>$department->id,
        ]
      );
     $newOpportunity ->save();
}

Answer 3

我认为您需要更新代码，如：

如果单个记录需要id：

 $department_id = Department::where('dep_name','=', $dep)->first();

 $newOpportunity = Opportunity::create(
           [
               'category'=>$request->category,
               'opportunity'=>$request->description,
               'vacancies'=>$request->positions,
               'department_id'=>$department_id->id,
           ]
         );

或者你需要id多条记录：

 $department_id = Department::select('id')->where('dep_name','=', $dep)->get();

 foreach($department_id as $department_ids){

   $newOpportunity = Opportunity::create(
           [
               'category'=>$request->category,
               'opportunity'=>$request->description,
               'vacancies'=>$request->positions,
               'department_id'=>$department_ids->id,
           ]
         );
 }

希望这会对你有所帮助。

Answer 4

你真的不需要这个系列。您需要具有一个属性的单个记录 - id。您的代码非常脏。尝试避免检索未使用的数据，如下所示：$department=Department::all();

下面的代码从数据库 ONLY ONE 记录中检索，这是正确的方法：

$department = Department::select('id')->where('dep_name','=', $request->department)->first();

完整代码：

public function store(Request $request)
{
   $this->validate($request,[
        'department' => 'required',
        'category' => 'required',
        'description' => 'required|string',
        'positions' => 'required|integer'
   ]);

   $department = Department::select('id')->where('dep_name','=', $request->department)->first();
   if($department) {
        $newOpportunity = Opportunity::create([
             'category' => $request->category,
             'opportunity' => $request->description,
             'vacancies' => $request->positions,
             'department_id' => $department->id,
        ]);
        $newOpportunity->save();
   }

   return redirect('admin/');  
}

从具有laravel雄辩的表中选择数据

4 个答案: