我有一个带有交货时间的订单和应收账款数据框。 我可以使用dplyr根据组提前期填写接收列吗?
df <- data.frame(team = c("a","a","a","a", "a", "b", "b", "b", "b", "b"),
order = c(2, 4, 3, 5, 6, 7, 8, 5, 4, 5),
lead_time = c(3, 3, 3, 3, 3, 2, 2, 2, 2, 2))
>df
team order lead_time
a 2 3
a 4 3
a 3 3
a 5 3
a 6 3
b 7 2
b 8 2
b 5 2
b 4 2
b 5 2
并添加如下接收列:
dfb <- data.frame(team = c("a","a","a","a", "a", "b", "b", "b", "b", "b"),
order = c(2, 4, 3, 5, 6, 7, 8, 5, 4, 5),
lead_time = c(3, 3, 3, 3, 3, 2, 2, 2, 2, 2),
receive = c(0, 0, 0, 2, 4, 0, 0, 7, 8, 5))
>dfb
team order lead_time receive
a 2 3 0
a 4 3 0
a 3 3 0
a 5 3 2
a 6 3 4
b 7 2 0
b 8 2 0
b 5 2 7
b 4 2 8
b 5 2 5
我正在考虑这些问题,但遇到了错误
dfc <- df %>%
group_by(team) %>%
mutate(receive = if_else( row_number() < lead_time, 0, lag(order, n = lead_time)))
Error in mutate_impl(.data, dots) :
could not convert second argument to an integer. type=SYMSXP, length = 1
感谢您的帮助!
答案 0 :(得分:2)
这看起来像一个bug;在lag
和dplyr
包之间可能存在stats
函数的某些意外掩码,请尝试以下方法:
df %>%
group_by(team) %>%
# explicitly specify the source of the lag function here
mutate(receive = dplyr::lag(order, n=unique(lead_time), default=0))
#Source: local data frame [10 x 4]
#Groups: team [2]
# team order lead_time receive
# <fctr> <dbl> <dbl> <dbl>
#1 a 2 3 0
#2 a 4 3 0
#3 a 3 3 0
#4 a 5 3 2
#5 a 6 3 4
#6 b 7 2 0
#7 b 8 2 0
#8 b 5 2 7
#9 b 4 2 8
#10 b 5 2 5
答案 1 :(得分:2)
我们也可以使用CBPeripheralManagerDelegate
shift
data.table