Question

是否可以在设置小数精度的同一行中设置字段填充的长度？我希望firstPlaceTime显示3个小数点，如8.250而不是8.25。也许像%8s%3f或%8s.3f这样的东西？谢谢:)）

System.out.format("%-10s%1s%-18s%1s%8s%1s%16s%-10s","Level " + level,  "| ", firstPlaceName, "| ", firstPlaceTime + "s ", "|", timeGain + "s ahead |", " " + numberOfRunners + " runners");

Answer 1

此代码显示了构建格式String以及使用%8.3f显示双精度的方法。

public static void main(String[] args)
{
    String level = "Beginning";
    String firstPlaceName = "TheWinner!";
    double firstPlaceTime = 180.234534D;
    double timeGain = 10.2D;
    int numberOfRunners = 10;

    StringBuilder sb = new StringBuilder();
    sb.append("Level %-10s"); //the level
    sb.append("|"); //divider
    sb.append("%-18s"); //name of winner
    sb.append("|"); //divider
    sb.append("%8.3f s "); //winning time
    sb.append("|"); //divider
    sb.append("%8.3f s ahead"); //time gain
    sb.append("|"); //divider
    sb.append("%5d runners"); // # of runners

    System.out.format(sb.toString(),
            level,
            firstPlaceName,
            firstPlaceTime,
            timeGain,
            numberOfRunners);

}

输出：

Level Beginning |TheWinner!        | 180.235 s |  10.200 s ahead|   10 runners

编辑：详细说明评论中的问题。 OP表示尝试使用%8.3f并收到格式错误。 firstPlaceTime是双倍的。但是，参数指定为：

...,firstPlaceTime + "s ",...

当+ "s "作为参数提供时，它会转换为String，然后传递给.format()。作为String，通过double规范进行格式化不会是%8.3f。这是建议将文本移动到格式规范而不是尝试的部分原因参数中的各种字符串连接。

同时设置字段填充和小数精度的长度

1 个答案: