我一直在尝试使用apache pdf框创建一个pdf三角形。 使用PDShadingType4类。下面是代码实现,但它只创建了空pdf。我没有在apache中提供的示例中找到任何PDShadingType4的实现。
生成的三角形应该看起来像pdf at左下角的三角形 link位于apache pdf框issue
中我无法使用PDShadingType4找到任何着色示例。</ p>
以下实施是否正确?或者它们是使用PDShadingType4
实现着色(三角形)的其他方法import java.io.IOException; import org.apache.pdfbox.cos.COSArray; import org.apache.pdfbox.cos.COSFloat; import org.apache.pdfbox.cos.COSInteger; import org.apache.pdfbox.cos.COSName; import org.apache.pdfbox.cos.COSStream; import org.apache.pdfbox.pdmodel.PDDocument; import org.apache.pdfbox.pdmodel.PDPage; import org.apache.pdfbox.pdmodel.PDPageContentStream; import org.apache.pdfbox.pdmodel.common.function.PDFunctionType2; import org.apache.pdfbox.pdmodel.graphics.color.PDDeviceRGB; import org.apache.pdfbox.pdmodel.graphics.shading.PDShading; import org.apache.pdfbox.pdmodel.graphics.shading.PDShadingType4; public class TriangleGraident2 { public void create(String file) throws IOException { PDDocument document = null; try { document = new PDDocument(); PDPage page = new PDPage(); document.addPage(page); PDPageContentStream contentStream = new PDPageContentStream(document, page, PDPageContentStream.AppendMode.APPEND, false); contentStream.moveTo(38, 17); COSStream fdict = new COSStream(); fdict.setInt(COSName.FUNCTION_TYPE, 2); COSArray cosArray = new COSArray(); cosArray.add(COSInteger.get(104)); cosArray.add(COSInteger.get(83)); cosArray.add(COSInteger.get(170)); cosArray.add(COSInteger.get(17)); cosArray.add(COSInteger.get(38)); cosArray.add(COSInteger.get(17)); /*Setting color */ COSArray c0 = new COSArray(); c0.add(COSFloat.get("1")); c0.add(COSFloat.get("0")); c0.add(COSFloat.get("0")); COSArray c1 = new COSArray(); c1.add(COSFloat.get("0.5")); c1.add(COSFloat.get("1")); c1.add(COSFloat.get("0.5")); /*Setting color*/ COSArray decode = new COSArray(); decode.add(COSFloat.get("0.0")); decode.add(COSFloat.get("1.0")); decode.add(COSFloat.get("0.0")); decode.add(COSFloat.get("1.0")); decode.add(COSFloat.get("0.0")); fdict.setItem(COSName.C0, c0); fdict.setItem(COSName.C1, c1); PDFunctionType2 func = new PDFunctionType2(fdict); PDShadingType4 shading = new PDShadingType4(fdict); shading.setColorSpace(PDDeviceRGB.INSTANCE); shading.setShadingType(PDShading.SHADING_TYPE4); shading.getCOSObject().setInt(COSName.LENGTH, 32); shading.setBitsPerCoordinate(24); shading.setBitsPerComponent(16); shading.setBitsPerFlag(8); shading.getCOSObject().setItem(COSName.COORDS, cosArray); shading.setDecodeValues(decode); shading.setFunction(func); contentStream.shadingFill(shading); contentStream.close(); document.save(file); document.close(); } finally { if (document != null) { document.close(); } } } public static void main(String[] args) throws IOException { TriangleGraident2 creator = new TriangleGraident2(); creator.create("C:\\Users\\abc\\Desktop\\triangle_image.pdf"); } }
答案 0 :(得分:2)
此代码在左下角创建一个Gouraud阴影三角形:
// See PDF 32000 specification,
// 8.7.4.5.5 Type 4 Shadings (Free-Form Gouraud-Shaded Triangle Meshes)
PDShadingType4 gouraudShading = new PDShadingType4(new COSStream());
gouraudShading.setShadingType(PDShading.SHADING_TYPE4);
// we use multiple of 8, so that no padding is needed
gouraudShading.setBitsPerFlag(8);
gouraudShading.setBitsPerCoordinate(16);
gouraudShading.setBitsPerComponent(8);
COSArray decodeArray = new COSArray();
// coordinates x y map 16 bits 0..FFFF to 0..FFFF to make your life easy
// so no calculation is needed, but you can only use integer coordinates
// for real numbers, you'll need smaller bounds, e.g. 0xFFFF / 0xA = 0x1999
// would allow 1 point decimal result coordinate.
// See in PDF specification: 8.9.5.2 Decode Arrays
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.get(0xFFFF));
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.get(0xFFFF));
// colors r g b map 8 bits from 0..FF to 0..1
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
gouraudShading.setDecodeValues(decodeArray);
gouraudShading.setColorSpace(PDDeviceRGB.INSTANCE);
// Function is not required for type 4 shadings and not really useful,
// because if a function would be used, each edge "color" of a triangle would be one value,
// which would then transformed into n color components by the function so it is
// difficult to get 3 "extremes".
OutputStream os = ((COSStream) gouraudShading.getCOSObject()).createOutputStream();
MemoryCacheImageOutputStream mcos = new MemoryCacheImageOutputStream(os);
// Vertex 1, starts with flag1
// (flags always 0 for vertices of start triangle)
mcos.writeByte(0);
// x1 y1 (left corner)
mcos.writeShort(0);
mcos.writeShort(0);
// r1 g1 b1 (red)
mcos.writeByte(0xFF);
mcos.writeByte(0);
mcos.writeByte(0);
// Vertex 2, starts with flag2
mcos.writeByte(0);
// x2 y2 (top corner)
mcos.writeShort(100);
mcos.writeShort(100);
// r2 g2 b2 (green)
mcos.writeByte(0);
mcos.writeByte(0xFF);
mcos.writeByte(0);
// Vertex 3, starts with flag3
mcos.writeByte(0);
// x3 y3 (right corner)
mcos.writeShort(200);
mcos.writeShort(0);
// r3 g3 b3 (blue)
mcos.writeByte(0);
mcos.writeByte(0);
mcos.writeByte(0xFF);
mcos.close();
// outside stream MUST be closed as well, see javadoc of MemoryCacheImageOutputStream
os.close();
运行着色,调用
contentStream.shadingFill(gouraudShading);
这是一个不同的解码数组,类似于你链接到的示例PDF中的解码数组,尽管我只使用了16位而不是24位:
COSArray decodeArray = new COSArray();
// coordinates x y map 16 bits 0..FFFF to -16384..16384
// this means that 0x8000 maps to 0
// some other useful values
// - 0x862C maps to top of A4 page
// - 0x84C4 maps to right of A4 page
// - 0x8262 maps to horizontal middle of A4 page
decodeArray.add(COSInteger.get(-16384));
decodeArray.add(COSInteger.get(16384));
decodeArray.add(COSInteger.get(-16384));
decodeArray.add(COSInteger.get(16384));
// colors r g b map 8 bits from 0..FF to 0..1
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
decodeArray.add(COSInteger.ZERO);
decodeArray.add(COSInteger.ONE);
gouraudShading.setDecodeValues(decodeArray);
三角形的坐标为0x8000 0x8000,0x8100 0x8100,0x8200 0x8000。