Question

我正在尝试将日期设定为从今天起的7个工作日（不包括周末和英国公众假期）。

我首先将默认日期设置为今天的日期（todaysDate）+ 7天（todayPlusSevenDays）
然后我计算今天之间的周末天数和日期。 todayPlusSevenDays 如果我发现任何我将它们添加到todayPlusSevenDays
然后我检查公众假期，如果我发现任何我也加了

执行这些检查后，我现在已经将额外的天数添加到我的默认日期 - 我怎样才能检查新的天数是否包含周末或公众假期？

例如，如果默认日期变为周末或银行假日，它还应该添加更多天数（现在它不会）。

到目前为止，这是我的代码： https://jsfiddle.net/7yxna052/

function prepopulateDropdown() {
    var todaysDate = new Date(),
        tempNewDate = new Date(),
        todayPlusSevenDays,
        numberOfWeekends,
        todayPlusSevenDaysPlusWeekends,
        currentHour = todaysDate.getHours(),
        holidayCount = 0,
        weekendDayCount = 0,
        ukHolidays = ['2017-05-12','2017-05-29','2017-08-28','2017-12-25','2017-12-26'];

    // check if current time < or > 6pm GMT
    function setDefaultdDate(){
     if(currentHour >= 18){
           todayPlusSevenDays = new Date(tempNewDate.setDate(tempNewDate.getDate() + 7));
       }
       else{
           todayPlusSevenDays = new Date(tempNewDate.setDate(tempNewDate.getDate() + 6));
       }
    }
    setDefaultdDate();

    // Weekend day count
    function calculateWeekendDays(startDate, endDate){
        while(startDate < endDate){
            startDate.setDate(startDate.getDate() + 1);
            if(startDate.getDay() === 0 || startDate.getDay() == 6){
                ++weekendDayCount ;
            }
        }
        return weekendDayCount;
    }
    calculateWeekendDays(todaysDate, todayPlusSevenDays);

    todayPlusSevenDaysPlusWeekends = new Date(tempNewDate.setDate(tempNewDate.getDate() + weekendDayCount));



    // count UK bank holidays within todayPlusSevenDays
    function calculateBankHolidays(startDate, endDate){
      startDate.setHours(0,0,0,0);
      endDate.setHours(0,0,0,0);

      for(i=0; i < ukHolidays.length; i++){
        ukHolidaysFormated = new Date(ukHolidays[i]).setHours(0,0,0,0);
        d = new Date(ukHolidays[i]).getDay();

        if (ukHolidaysFormated >= startDate && ukHolidaysFormated <= endDate && !(d == 0 || d == 6)) {
           holidayCount++;
        }
      }
      return holidayCount;
    }
    calculateBankHolidays(todaysDate, todayPlusSevenDaysPlusWeekends);

    todayPlusSevenDaysPlusWeekends = new Date(todayPlusSevenDaysPlusWeekends.setDate(todayPlusSevenDaysPlusWeekends.getDate() + holidayCount));


    // set date to prepopulate
    var today = new Date();
    var year = todayPlusSevenDaysPlusWeekends.getFullYear();
    var month = '0' + (todayPlusSevenDaysPlusWeekends.getMonth() + 1);
    var day = todayPlusSevenDaysPlusWeekends.getDate();

    $('.slctDay option').each(function(){
        if($(this).val() == day){
            $(this).attr('selected','selected');
        }
    });
    $('.slctMonth option').each(function(){
        if($(this).val() == month){
            $(this).attr('selected','selected');
        }
    });
    $('.slctYear option').each(function(){
        if($(this).val() == year){
            $(this).attr('selected','selected');
        }
    });
}

Answer 1

一次检查一天而不是7天范围。

首先将默认日期设置为今天的日期。然后，一次检查一天到未来。如果那天是工作日，请将workingDay计数器递增1.如果不是，则循环到第二天。当您的workingDay计数器达到7时，那就是您需要的日期。

Answer 2

以下是@andi所谈论的一个例子。我把它作为计算器对象。

＆＃13;

var calculator = {
    workDaysAdded: 0,
    ukHolidays: ['2017-05-12','2017-05-29','2017-08-28','2017-12-25','2017-12-26'],
    startDate: null,
    curDate: null,

    addWorkDay: function() {
        this.curDate.setDate(this.curDate.getDate() + 1);
        if(this.ukHolidays.indexOf(this.formatDate(this.curDate)) === -1 && this.curDate.getDay() !== 0 && this.curDate.getDay() !== 6) {
            this.workDaysAdded++;
        }
    },

    formatDate: function(date) {
        var day = date.getDate(),
            month = date.getMonth() + 1;

        month = month > 9 ? month : '0' + month;
        day = day > 9 ? day : '0' + day;
        return date.getFullYear() + '-' + month + '-' + day;
    },

    getNewWorkDay: function(daysToAdd) {
        this.startDate = new Date();
        this.curDate = new Date();
        this.workDaysAdded = 0;
        
        while(this.workDaysAdded < daysToAdd) {
            this.addWorkDay();
        }
        return this.curDate;
    }
}

var newWorkDay7 = calculator.getNewWorkDay(7);
var newWorkDay9 = calculator.getNewWorkDay(9);
var newWorkDay14 = calculator.getNewWorkDay(14);
console.log(newWorkDay7);
console.log(newWorkDay9);
console.log(newWorkDay14);

＆＃13;

Answer 3

如果您只想添加7天并且不包括假日和周末（假设星期六和星期日），那么您可以从开始到结束步骤并在每天进行测试：

＆＃13;

var ukHolidays = ['2017-05-12','2017-05-29','2017-08-28','2017-12-25','2017-12-26'];

// Return date string in format YYYY-MM-DD
function getISODate(date){
  function z(n) {return (n<10?'0':'')+n}
  return date.getFullYear() + '-' + z(date.getMonth() + 1) + '-' + z(date.getDate());  
}

// Modifies date by adding 7 days, excluding sat, sun and UK holidays
function add7WorkingDays(date) {
  for (var i=7; i; i--) {
    // Add a day
    date.setDate(date.getDate() + 1);

    // If a weekend or holiday, keep adding until not
    while(!(date.getDay()%6) || ukHolidays.indexOf(getISODate(date)) != -1) {
      date.setDate(date.getDate() + 1);
    }
  }
  return date;
}

// Add 7 working days to today
var d = new Date();
console.log('Add 7 working days to ' + d.toString() + 
            '\nResult: ' + add7WorkingDays(d).toString());

＆＃13;

将日期设定为今天起7个工作日（周末及公众假期除外）

3 个答案: