我有一个Azure移动应用服务,PullAsync
无声地失败。
在后端,DTO看起来像这样:
type TablesDto() =
[<JsonProperty("id")>] member val Id = String.Empty with get, set
[<JsonProperty("deleted")>] member val Deleted = false with get, set
[<JsonProperty("createdAt")>] member val CreatedAt = Nullable<DateTimeOffset>() with get, set
[<JsonProperty("updatedAt")>] member val UpdatedAt = Nullable<DateTimeOffset>() with get, set
[<JsonProperty("version")>] member val Version = [||] with get, set
interface ITableData with
member this.Id with get() = this.Id and set(value) = this.Id <- value
member this.Deleted with get() = this.Deleted and set(value) = this.Deleted <- value
member this.CreatedAt with get() = this.CreatedAt and set(value) = this.CreatedAt <- value
member this.UpdatedAt with get() = this.CreatedAt and set(value) = this.UpdatedAt <- value
member this.Version with get() = this.Version and set(value) = this.Version <- value
type MyEntityDto() =
inherit TablesDto()
[<JsonProperty("entityName")>] member val EntityName = String.Empty with get, set
我正在使用DomainManager
将我的数据库架构中的对象映射到此DTO表单中,但我不确定它是否相关。
在前端(在Xamarin Android应用程序中),DTO定义为
type MyEntityDto() =
[<JsonProperty("id")>] member val Id = String.Empty with get, set
[<JsonProperty("version"); AzureVersion>] member val Version = Unchecked.defaultof<String> with get, set
[<JsonProperty("createdAt")>] member val CreatedUtc = DateTime.MinValue with get, set
[<JsonProperty("updatedAt")>] member val UpdatedUtc = DateTime.MinValue with get, set
[<JsonProperty("entityName")>] member val EntityName = String.Empty with get, set
出于调试目的,我使用以下处理程序来检查从服务器返回的JSON:
#if DEBUG
type DebuggingHandler() =
inherit DelegatingHandler()
let deserialise content =
try
let deserialised = JsonConvert.DeserializeObject<MyEntitypDto[]>(content)
deserialised |> ignore
with
| ex ->
ex |> ignore
override this.SendAsync(message, cancellationToken) =
let sendAsync = base.SendAsync(message, cancellationToken)
async {
let! response = sendAsync |> Async.AwaitTask
let! content = response.Content.ReadAsStringAsync() |> Async.AwaitTask
deserialise content
return response
} |> Async.StartAsTask
#endif
检查调试器中的content
值显示:
[{"myEntityName@":"Harry","id@":"2","deleted@":true,"createdAt@":"2017-04-26T11:20:46.83Z","updatedAt@":"2017-04-26T11:20:46.83Z","version@":"AAAAAAAAO/Y="},
{"myEntityName@":"Gary","id@":"3","deleted@":false,"createdAt@":"2017-04-26T11:23:05.16Z","updatedAt@":"2017-04-26T11:23:05.16Z","version@":"AAAAAAAAO/c="}]
这个“@”符号后缀发生了什么?它可以防止对象在调试器中反序列化,我怀疑这就是PullAsync
方法回收的原因。
这是F#的一些奇怪的副作用吗?如何摆脱这些“@”符号(如果这是导致我的表同步中断的原因)?
编辑我添加了一个C#标记,因为这可能与典型企业环境中F#和C#之间的差异有关。
答案 0 :(得分:2)
费奥多尔的评论是我需要找到答案的提示。
在Azure移动应用程序中,使用表控制器开箱即用的JSON格式化程序无法正确序列化F#对象。因此,您需要进行以下自定义:
创建一个使用JSON.Net的格式化程序:
type JsonDotNetFormatter() as this =
inherit MediaTypeFormatter()
do this.SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/json"))
let settings = new JsonSerializerSettings(ReferenceLoopHandling = ReferenceLoopHandling.Ignore)
do settings.ContractResolver <- new CamelCasePropertyNamesContractResolver()
override __.CanReadType _ = true
override __.CanWriteType _ = true
override __.ReadFromStreamAsync(t, readStream, _, _) =
async {
use reader = new StreamReader(readStream)
let! text = reader.ReadToEndAsync() |> Async.AwaitTask
return JsonConvert.DeserializeObject(text, t)
} |> Async.StartAsTask
override __.WriteToStreamAsync(_, value, writeStream, _, _) =
async {
match box value with
| null -> value |> ignore
| _ ->
let text = JsonConvert.SerializeObject(value, settings)
use writer = new StreamWriter(writeStream)
do! writer.WriteAsync(text) |> Async.AwaitTask
} |> Async.StartAsTask :> Task
创建配置提供程序,以便在Startup.MobileApp.cs
中使用:
public class JsonDotNetConfigProvider : TableControllerConfigProvider
{
public override void Configure(HttpControllerSettings controllerSettings, HttpControllerDescriptor controllerDescriptor)
{
base.Configure(controllerSettings, controllerDescriptor);
controllerSettings.Formatters.Insert(0, new JsonDotNetFormatter());
}
}
使用Startup.Configure()
方法将配置提供程序添加到您的移动应用配置中:
new MobileAppConfiguration()
.AddTablesWithEntityFramework()
.WithTableControllerConfigProvider(new JsonDotNetConfigProvider())
.ApplyTo(config);
如果您遇到与F#无关的其他通用序列化问题,这也应该有效。我在这个例子中混合了C#和F#,但如果你想编写基于F#的企业级软件,那么你可能需要做的事情。