Question

我是新手，也是python的初学者，所以请帮助我。我已经完成了以下操作来创建一个程序，该程序告诉用户输入的数字是Up，Down还是输入的第一个数字相同。我的问题是，如何为它创建一个循环，以便用户可以输入尽可能多的数字，然后在输入0时结束进程？

print ('Please enter your first number')
firstNumber = input()

print('Enter the next number(0 to finish)')
nextNumber=input()

if firstNumber<nextNumber:
    print ('Up')

if firstNumber>nextNumber:
    print ('Down')

if firstNumber==nextNumber:
    print ('Same')

谢谢

Answer 1

从英语翻译成python，你想要的是

while nextNumber != 0:
    ...keep looping...

因此，在不更改代码的情况下，您可以执行以下操作：

print ('Please enter your first number')
firstNumber = input()

print('Enter the next number(0 to finish)')
nextNumber=input()

while nextNumber != 0:

    if firstNumber<nextNumber:
        print ('Up')

    if firstNumber>nextNumber:
        print ('Down')

    if firstNumber==nextNumber:
        print ('Same')

    # turn the nextNumber into the firstNumber
    firstNumber = nextNumber

    print('Enter the next number(0 to finish)')
    nextNumber=input()

您还可以改进一些事项。例如，您不需要在print之前使用input语句。你可以简单地做input('Please enter your first number')。此外，您可以使用if - else而不是if。

以下是它的外观示例：

firstNumber = input('Please enter your first number')

nextNumber=input('Enter the next number(0 to finish)')

while nextNumber != 0:

    if firstNumber<nextNumber:
        print ('Up')

    elif firstNumber>nextNumber:
        print ('Down')

    elif firstNumber==nextNumber:
        print ('Same')

    # turn the nextNumber into the firstNumber
    firstNumber = nextNumber

    nextNumber=input('Enter the next number(0 to finish)')

现在，您说要收集所有Ups和Downs并在最后打印它们。您只需创建list并将值附加到list即可。像这样：

ups_and_downs = []

firstNumber = input('Please enter your first number')

nextNumber=input('Enter the next number(0 to finish)')

while nextNumber != 0:

    if firstNumber<nextNumber:
        ups_and_downs.append('Up')
        print ('Up')

    elif firstNumber>nextNumber:
        ups_and_downs.append('Down')
        print ('Down')

    elif firstNumber==nextNumber:
        ups_and_downs.append('Same')
        print ('Same')

    # turn the nextNumber into the firstNumber
    firstNumber = nextNumber

    nextNumber=input('Enter the next number(0 to finish)')

print(ups_and_downs)

Answer 2

nextNumber = 1 #define 
while nextNumber != 0: #as long as its not 0, run loop
  print ('Please enter your first number')
  firstNumber = int(input()) #python treats input as str so cast to int

  print('Enter the next number(0 to finish)')#cast str to int
  nextNumber= int(input())

  if firstNumber<nextNumber:
      print ('Up')

  if firstNumber>nextNumber:
      print ('Down')

  if firstNumber==nextNumber:
      print ('Same')

输出：

Please enter your first number
 4
Enter the next number(0 to finish)
 6
Up
Please enter your first number
 7
Enter the next number(0 to finish)
 8
Up
Please enter your first number
 5
Enter the next number(0 to finish)
 4
Down
Please enter your first number
 8
Enter the next number(0 to finish)
 0
Down

Answer 3

firstNumber = input('Please enter your first number ') # ask for the first number
fn = int(firstNumber) # turn into an integer to compare

while True: # start a loop
    nextNumber = input('Enter the next number (0 to finish) ') # ask for another number
    nn = int(nextNumber)
    if nn == 0: break # leave the loop if the new number is 0
    if fn<nn: print('Up') # compare
    if fn>nn: print('Down')
    if fn==nn: print('Same')

通过按0循环代码并结束循环

3 个答案: