Question

我创建了一个查询来显示当前年份的数据以及当前年份数据不存在的行显示上一年的数据，但现在的问题是那些有现有年度数据的公司将上一年的数据显示为井

数据库company_annual_data

 +--id--+---company_id----+----year-----+----number_of_shares_issued----+
+   1  +     20          +    2011     +              425              +
+   2  +     21          +    2011     +              425              +
+   3  +     22          +    2011     +              425              +
+   4  +     23          +    2011     +              425              +
+   5  +     21          +    2012     +              425              +
+   6  +     20          +    2012     +              425              +
+   7  +     23          +    2012     +              425              +
+   8  +     20          +    2013     +              425              +

公司

+--id--+---company_name----+----category-----+
+  20  +     Company 1     +       2         +
+  21  +     Company 2     +       2         +
+  22  +     Company 3     +       2         +
+  23  +     Company 4     +       5         +

这是我的查询

$sql            = mysqli_query($connect, "SELECT * FROM companies WHERE category = '36'");
    $total_count    = mysqli_num_rows($sql);
    $companies = array();


    while($row = mysqli_fetch_assoc($sql)) {
            $companies[] = $row['id'];
    }

    $ids = join(', ', $companies);

    $sql1         = mysqli_query($connect, "SELECT year FROM companies_annual_data WHERE company_id IN ($ids) ORDER BY year DESC LIMIT 0, $total_count");
    $total_count1 = mysqli_num_rows($sql1);
    $year     = array();

    $prev_val = null;       
    while($total_year = mysqli_fetch_assoc($sql1)) {
        if($total_year['year'] != $prev_val) {
            $year[] =  $total_year['year'];
        }
        $prev_val = $total_year['year'];    
    }

    $years      = join(', ', $year);
    $sql2       = mysqli_query($connect, "SELECT DISTINCT number_of_shares_issued, year, company_id FROM companies_annual_data WHERE company_id IN ($ids) AND year IN ($years)");
    $prev_val_y = null;
    while($share_num = mysqli_fetch_assoc($sql2)) {
        if($share_num['year'] != date('Y')) {
            echo "Number Of Shares : " . $share_num['number_of_shares_issued'];
            echo " Year : " . $share_num['year'];
            echo " Company Id : " . $share_num['company_id'];
            echo "<br />";
        }
    }

这是输出

Number Of Shares : 284125000 Year : 2015 Company Id : 348
Number Of Shares : 100000000 Year : 2015 Company Id : 351
Number Of Shares : 152098344 Year : 2015 Company Id : 356
Number Of Shares : 152098334 Year : 2016 Company Id : 356
Number Of Shares : 283500000 Year : 2015 Company Id : 366
Number Of Shares : 283500000 Year : 2016 Company Id : 366

输出应该是这样的错误

Number Of Shares : 284125000 Year : 2015 Company Id : 348
Number Of Shares : 100000000 Year : 2015 Company Id : 351
Number Of Shares : 152098334 Year : 2016 Company Id : 356
Number Of Shares : 283500000 Year : 2016 Company Id : 366

任何人都可以帮我解决这个问题

Answer 1

如果我理解这个问题......

这将返回所提供的每家公司的最新年度记录数据类别是36

SELECT CAD.num_of_Shares_Issued, CAD.`Year`, CAD.Company_ID
FROM Companies C
INNER JOIN (SELECT max(`year`) MYear, Company_ID 
            FROM company_Annual_data 
            GROUP BY Company_ID) SUB
 on SUB.CompanyID = C.Company_ID
LEFT JOIN Company_Annual_data CAD
 on C.ID = CAD.Company_ID
and SUB.MYear = CAD.`year`
WHERE  C.Category = 36

如果当前年份的数据不显示上一年

1 个答案: