Question

我有2个表从数据库中检索，有2个不同的查询，需要在json中编码并发送到ajax。问题是我无法将2个json传递给ajax。我试过echo echo json_encode（array（$ data1，$ data2））;但它没有用。

//我的PHP代码

$query = $db->query("select * from table1 where valu1='".$value1."'");
while ($row = $query->fetch_assoc()) {
    $data1['value1'] = $row['value1'];
    $data1['value2'] = $row['value2'];
}
$query = $db->query("select * from table2 where value2='".$value2."' ");
while ($row = $query->fetch_assoc()) {
    $data2['value2'] = $row['value2'];
    $data2['value3'] = $row['value3'];
}

  echo json_encode(array($data1,$data2));

//我的AJAX代码

$(document).ready(function(){
  $('#Form').submit(function(e){
  e.preventDefault(); // stops the form submission

  $.ajax({
     url:$(this).attr('action'), // action attribute of form to send the values
   type:$(this).attr('method'), // method used in the form
   data:$(this).serialize(), // data to be sent to php
   dataType:"json",
   success:function(data){
       //main
       alert(data.value1);
   },
   error:function(err){
       alert(err);
   }
 });

});
});

请帮助解决这个问题。谢谢提前

Answer 1

在PHP中：

echo json_encode(array($data1, $data2));

在AJAX中：

var data1 = data[0];
var data2 = data[1];
$.each(data1, function() {
    console.log(this.value1 + ',' + this.value2);
});
$.each(data2, function() {
    console.log(this.value2 + ',' + this.value3);
});

修改经过整整一年，我只是注意到最初的PHP代码是错误的，因为sql结果的循环每次都会覆盖数组的值。所以，正确的是：

$query = $db->query("select * from table1 where valu1='".$value1."'"); while ($row = $query->fetch_assoc()) { $data1[] = array('value1' => $row['value1'], 'value2' => $row['value2']); } $query = $db->query("select * from table2 where value2='".$value2."' "); while ($row = $query->fetch_assoc()) { $data2[] = array('value2' => $row['value2'], 'value3' => $row['value3']); } echo json_encode(array($data1,$data2));

Answer 2

您的代码很好，您只需处理成功函数中的两个数组：

success: function(data){
  var object1 = data[0];
  var object2 = data[1];

  // Do whatever you like to do with them
}

json_encode超过2个数组

2 个答案: