插入数据(如果不存在),如果数据存在重复则替换MySQL中的旧数据

时间:2017-05-03 10:22:24

标签: mysql replace duplicates

首先,我想将从谷歌API获得的数据插入MySQL。我可以将数据插入我的数据库中。但我遇到了一个问题,如果数据相同,它将不会取代旧数据。我想要替换的数据是片段,但如果链接相同但片段不同,则会创建新的而不是替换。我已经尝试过使用INSERT IGNORE INTO,但它都插入新数据而不是替换它,我使用REPLACE INTO但它也一样。这是我的编码。

<html>  
      <head>  
           <title>Media Monitoring</title> 

     <style>

   .box
   {
    width:750px;
    padding:20px;
    background-color:#fff;
    border:1px solid #ccc;
    border-radius:5px;
    margin-top:100px;
   }
  </style>
      </head>  
      <body>  
        <div class="container box">
          <h3 align="center">Import JSON File Data into Mysql Database in PHP</h3><br />
          <?php
          $connect = mysqli_connect("localhost", "root", "", "accounts"); //Connect PHP to MySQL Database
          $query = '';
          $table_data = '';

          $filename = 'https://www.googleapis.com/customsearch/v1?q=unimap&cx=004123968310343535430%3Aaxml6iel9yo&key=AIzaSyDxPcphnrcN9_dfkRkFTbwkv44m1-HI1Hg&sort=date';
          $data = file_get_contents($filename); //Read the JSON file in PHP
          $array = json_decode($data, true); //Convert JSON String into PHP Array
          //$record =$array['items'][1]["link"];
         // var_dump($record);
          foreach($array['items'] as $row) //Extract the Array Values by using Foreach Loop
          {
           // $query .="SELECT * from go WHERE htmlSnippet ='" 
           $query .= "INSERT INTO go(htmlTitle, Link, htmlSnippet) VALUES ('".$row["htmlTitle"]."', '".$row["link"]."', '".$row["htmlSnippet"]."') ;";  // Make Multiple Insert Query 
           $table_data .= '
            <tr>
       <td>'.$row["htmlTitle"].'</td>
       <td>'.$row["link"].'</td>
       <td>'.$row["htmlSnippet"].'</td>
      </tr>
           '; //Data for display on Web page
          }
          if(mysqli_multi_query($connect, $query)) //Run Mutliple Insert Query
    {
     echo '<h3>Imported JSON Data</h3><br />';
     echo '
      <table class="table table-bordered">
        <tr>
         <th width="45%">Name</th>
         <th width="10%">Gender</th>
         <th width="45%">Designation</th>
        </tr>
     ';
     echo $table_data;  
     echo '</table>';
          }




          ?>
     <br />
         </div>  
      </body>  
 </html> 

0 个答案:

没有答案