从shell脚本中的文本文件解析和更新xml文件（使用xmlstarlet）

Question

我有一个xml文件，我想根据文本文件中的值更改节点值。 所以基本上这是xml文件 - ＆gt; 001.xml

<?xml version="1.0" encoding="UTF-8"?>
<Orderfile xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
  <order>
    <establishmenthour>10:38:00</ establishmenthour>
    <ExpirationDate/>
    <acc/>
    <identification>170610009-01</identification>
  </order>
  <order>
    <establishmenthour>10:40:00</ establishmenthour>
    <ExpirationDate/>
    <acc/>
    <identification>170610910-03</identification>
  </order>
  <order>
    <establishmenthour>10:42:00</ establishmenthour>
    <ExpirationDate/>
    <acc/>
    <identification>170610015-01</identification>
  </order>

这是我的文本文件

170610009-01;2017-06-21
170610015-01;2017-02-22

我想拥有什么

<?xml version="1.0" encoding="UTF-8"?>
<Orderfile xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
  <order>
    <establishmenthour>10:38:00</establishmenthour>
    <ExpirationDate>2017-06-21</ExpirationDate/>
    <acc/>
    <identification>170610009-01</identification>
  </order>
  <order>
    <establishmenthour>10:40:00</ establishmenthour>
    <ExpirationDate/>
    <acc/>
    <identification>170610910-03</identification>
  </order>
  <order>
    <establishmenthour>10:42:00</ establishmenthour>
    <ExpirationDate>2017-02-22</ExpirationDate/>
    <acc/>
    <identification>170610015-01</identification>
  </order>

我决定使用xmlstarlet编写一个bash脚本，但它似乎不起作用

 #!/bin/bash

    while read line; do

       last10=${line:14:23}
       first12=${line:0:12}

    if /orderFile/order[identification = '${first12}']
    then xmlstarlet ed -u /orderFile/order[@expirationDate]/@expirationDate -v "${last10}"  001.xml
fi
    done < datevalid.txt

我哪里错了？