Question

我最近刚刚完成了一些非常基本的故障排除系统的代码。我只是想添加一些验证，以便如果用户在任何问题上输入任何不是或否的内容，那么它将在shell中打印“无效输入”，但不确定如何完全执行此操作。有谁可以帮助我吗？非常感谢。

我的代码：

prompt = "> "

print ("screen question one here")
screen = input(prompt)
if screen == "yes":
    print ("screen question two here")
    screen2 = input(prompt)
    if screen2 == "yes":
        print ("screen question three here")
        screen3 = input(prompt)
        if screen3 == "yes":
            print ("screen advice one here")
        elif screen3 == "no":
            print ("screen adivce two here")
    elif screen2 == "no":
        print ("camera question one here")
        camera = input(prompt)
        if camera == "yes":
            print ("camera question two here")
            camera2 = input(prompt)
            if camera2 == "yes":
                print ("camera advice one here")
            elif camera2 == "no":
                print ("camera advice two here")
        elif camera == "no":
            print ("water question one here")
            water = input(prompt)
            if water == "yes":
                print ("water question two here")
                water2 = input(prompt)
                if water2 == "yes":
                    print ("water advice one here")
                elif water2 == "no":
                    print ("water advice two here")
            elif water == "no":
                print ("buttons question one here")
                buttons = input(prompt)
                if buttons == "yes":
                    print ("buttons advice one here")
                elif buttons == "no":
                    print ("buttons advice two here")  
elif screen == "no":
    print ("battery question one here")
    battery = input(prompt)
    if battery == "yes":
        print ("battery question two here")
        battery2 = input(prompt)
        if battery2 == "yes":
            print ("battery advice one here")
        elif battery2 == "no":
            print ("battery advice two here")
    elif battery == "no":
        print ("wifi question one here")
        wifi = input(prompt)
        if wifi == "yes":
            print ("wifi advice one here")
        elif wifi == "no":
            print ("wifi advice two here")

Answer 1

这是你可能采取的一种方式。

定义一个从用户获得“是”或“否”的函数。人们倾向于想要重复这个问题，直到用户给你一个合适的答案：这就是这个功能所做的。

def yesorno(question):
    while True:
        print(question)
        answer = input('> ').strip().lower()
        if answer in ('y', 'yes'):
            return True
        if answer in ('n', 'no'):
            return False
        print("Invalid input")

另一方面，如果您只是想在输入无效时退出脚本，可以这样做：

def yesorno(question):
    print(question)
    answer = input('> ').strip().lower()
    if answer in ('y', 'yes'):
        return True
    if answer in ('n', 'no'):
        return False
    exit('Invalid input')

exit只会退出整个程序。它不一定是我推荐的。

无论哪种方式，您都可以像这样使用yesorno：

if yesorno("Question 1"):
    # User answered yes
    if yesorno("Question 2A"):
        # User answered yes
    else:
        # User answered no
else:
    # User answered no
    if yesorno("Question 2B"):
        ...

如何在python中打印错误？

1 个答案: