Question

我正在开发一个带有节点JS的应用程序，该应用程序会生成一个调用端点的报告api.example.com/generate-report

但是这个报告大约需要1分钟生成，然后我想实现类似的东西：

用户点击生成报告
系统返回响应{generate：“ok”}
系统生成报告后发送通知（这是我知道该怎么做）
用户获取报告

这可以用nodejs吗？

Answer 1

在我做了一些研究后，可以使用Promises轻松完成。

要运行以下代码，必须安装express和node uuid

npm install --save express
npm install --save uuid
node index.js

索引的源代码是：

//index.js
const express = require("express");
const app = express();
const PORT = process.env.PORT || 5000;
const uuidV1 = require('uuid/v1');

// this is where we'll store the results of our jobs by uuid once they're done
const JOBS = {};

app.get("/", (req, res) => {
  res.send("It works!");
});

app.get("/startjob", (req, res) => {
  let times = [100, 1000, 10000, 20000];
  let promises = [];
  for (let time of times) {
    promises.push(new Promise((resolve, reject) => {
      setTimeout(resolve, time, `${time} is done.`);
    }));
  }
  // obviously, you'd want to generate a real uuid here to avoid collisions
  let uuid = uuidV1();
  console.log(uuid);
  Promise.all(promises).then(values => { JOBS[uuid] = values; });
  res.redirect(`progress/${uuid}`);
});

app.get("/progress/:uuid", (req, res) => {
  if (JOBS[req.params.uuid] === undefined) {
    res.send("Still processing your request.");
  } else {
    res.send(`Here's your result: ${JOBS[req.params.uuid]}.`);
    // instead of immediately deleting the result of the job (and making it impossible for the user
    // to fetch it a second time if they e.g. accidentally cancel the download), it would be better
    // to run a periodic cleanup task on `JOBS`
    delete JOBS[req.params.uuid];
  }
});

app.listen(PORT, () => {
  console.log(`Listening on localhost:${PORT}.`);
});

当代码运行时，您将被重定向到/ process / uuid，我将获得该进程的状态。

这需要一些改进，因为我想要像＆＃34; {process：uuid}＆＃34;我可以将它存储在我的本地存储上以便在之后使用。

嗯，我希望这对某人有所帮助。

Nodejs Api在后台调用

1 个答案: