我有一种基于ASP.Net构建的旧式Web服务。通过以下功能,我能够从asmx Web服务中获取某些类型的数据:
func getJsonData(sql: String, spparamnames: String, spParamValues: String, completeonClosure: @escaping (AnyObject?) -> ()) {
let url = URL(string:"http://www.example.com/MyWebService.asmx/GetDataTableAsJson")
var request = URLRequest(url: url!)
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type") // the request is JSON
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Accept") // the expected response is also JSON
request.httpMethod = "POST"
let dictionary = ["sql" : sql, "spparamnames" : spparamnames, "spparamvalues" : spParamValues] //Parameters are here seperated with comma
request.httpBody = try! JSONSerialization.data(withJSONObject: dictionary)
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else {
print(error.debugDescription) // some fundamental network error
return
}
do {
if response != nil {
let myJson = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.mutableContainers) as! [String:AnyObject]
let isCorectJson = JSONSerialization.isValidJSONObject(myJson)
let charcount = (myJson["d"] as? String)?.characters.count
let cc = charcount ?? 0
if isCorectJson == true && cc > 0 {
completeonClosure(myJson as AnyObject?)
)
} else {
let str2 = "Connection Error"
completeonClosure(str2 as AnyObject?)
}
}
} catch let JsonError {
print(JsonError)
}
}
task.resume()
}
当我使用Swift运行查询并将对象类型转换为NSDictionary
时,我的输出结果如下:
getJsonData(sql: "SELECT TOP 3 User_id, LoweredUserName FROM Users", spparamnames: "", spParamValues: "") {
returnJSON in
OperationQueue.main.addOperation {
let mystr = returnJSON as? NSDictionary
print(mystr!)
}
}
结果:
{
d = "[{\"User_id\":102,\"LoweredUserName\":\"abu alay\"},{\"User_id\":90,\"LoweredUserName\":\"ali es\"},{\"User_id\":95,\"LoweredUserName\":\"alper ay\"}]";
}
我认为结果是某种字典,我无法将结果转换为数组,因此我无法在行之间进行迭代并有效地使用结果。我应该怎么做才能读取结果:print(returnJSON [0] [" LoweredUserName"])?这封信是什么意思" d"在结果的开头?非常感谢提前。
答案 0 :(得分:0)
看起来您的响应是一个Array,尝试转换为一个字典对象数组。
if let myJson = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.mutableContainers) as? [[String:AnyObject]] {
// parse each object here
}
我在操场上运行的这个示例代码似乎工作正常:
let jsonString = "[{\"User_id\":102,\"LoweredUserName\":\"abu alay\"},{\"User_id\":90,\"LoweredUserName\":\"ali es\"},{\"User_id\":95,\"LoweredUserName\":\"alper ay\"}]"
let jsonData = jsonString.data(using: String.Encoding.utf8)
if let json = try? JSONSerialization.jsonObject(with: jsonData!, options: .mutableContainers) as? [[String:AnyObject]] {
print(json)
}
输出:
Optional([["User_id": 102, "LoweredUserName": abu alay], ["User_id": 90, "LoweredUserName": ali es], ["User_id": 95, "LoweredUserName": alper ay]])
答案 1 :(得分:0)
如果您显示的文字是您获得的结果的全部内容:
{
d = "[{\"User_id\":102,\"LoweredUserName\":\"abu alay\"},{\"User_id\":90,\"LoweredUserName\":\"ali es\"},{\"User_id\":95,\"LoweredUserName\":\"alper ay\"}]";
}
然后这是没有正确格式化的JSON。为了正确格式化," d"必须用双引号显示。
看起来您可能需要对结果进行一些自定义解析以获取" d"中包含的JSON。区域。