Question

如何获取使用pivot创建的这组数据。

Country town1       City1       town2       City2       town3   City3       town4   City4       town5   City5
India   NULL        NULL        NULL        NULL        NULL    NULL        townin  India Town  NULL    NULL
India   NULL        NULL        NULL        NULL        Del     New Delhi   NULL    NULL        NULL    NULL
India   NULL        NULL        Bang        Bangalore   NULL    NULL        NULL    NULL        NULL    NULL
India   hyder       Hyderabad   NULL        NULL        NULL    NULL        NULL    NULL        NULL    NULL
UK      NULL        NULL        NULL        NULL        United  Manchester  NULL    NULL        NULL    NULL
UK      NULL        NULL        sunderland  Birmingham  NULL    NULL        NULL    NULL        NULL    NULL
UK      chelsea     London      NULL        NULL        NULL    NULL        NULL    NULL        NULL    NULL
USA     NULL        NULL        NULL        NULL        Dally   Dallas      NULL    NULL        NULL    NULL
USA     NULL        NULL        houst       Houston     NULL    NULL        NULL    NULL        NULL    NULL
USA     New Jersy   New York    NULL        NULL        NULL    NULL        NULL    NULL        NULL    NULL

看起来像这样的数据，这是我需要显示的内容：

Country town1       City1       town2       City2       town3   City3       town4   City4       town5   City5
India   hyder       Hyderabad   Bang        Bangalore   Del     New Delhi   townin  India Town  NULL    NULL
UK      chelsea     London      sunderland  Birmingham  United  Manchester  NULL    NULL        NULL    NULL
USA     New Jersy   New York    houst       Houston     Dally   Dallas      NULL    NULL        NULL    NULL

我使用了下面的创建和插入代码：

Create Table Countries
(
    Country nvarchar(50),
    Town nvarchar(50),
    City nvarchar(50)
)
GO

Insert into Countries values ('USA','New Jersy','New York')
Insert into Countries values ('USA','houst','Houston')
Insert into Countries values ('USA','Dally','Dallas')

Insert into Countries values ('India','hyder','Hyderabad')
Insert into Countries values ('India','Bang','Bangalore')
Insert into Countries values ('India','Del','New Delhi')
Insert into Countries values ('India','townin','India Town')

Insert into Countries values ('UK','chelsea','London')
Insert into Countries values ('UK','sunderland','Birmingham')
Insert into Countries values ('UK','United','Manchester')

基于一些博客和视频的当前数据透视代码：

Select Country, town1, City1, town2, City2, town3, City3, town4, City4, town5, City5
From
(
Select Country, City, 'City'+ cast(row_number() over(partition by Country order by Country) as varchar(10)) ColumnSequence,
Town, 'Town'+ cast(row_number() over(partition by Country order by Country) as varchar(10)) ColumnSequence2 
from Countries
) Temp
pivot
(
max(City)
for ColumnSequence in (City1, City2, City3, City4, City5) 
) Piv
pivot
(
max(Town)
for ColumnSequence2 in (town1, town2, town3, town4, town5) 
) Piv
group by Country, town1, City1, town2, City2, town3, City3, town4, City4, 
town5, City5

Answer 1

使用row_number()和条件聚合来转移数据：

select 
    Country
  , Town_01 = max(case when rn = 1 then Town end)
  , City_01 = max(case when rn = 1 then City end)
  , Town_02 = max(case when rn = 2 then Town end)
  , City_02 = max(case when rn = 2 then City end)
  , Town_03 = max(case when rn = 3 then Town end)
  , City_03 = max(case when rn = 3 then City end)
  , Town_04 = max(case when rn = 4 then Town end)
  , City_04 = max(case when rn = 4 then City end)
from (
  select *
    , rn = row_number() over (partition by Country order by Town) 
  from Countries
  ) as t
group by Country

rextester演示：http://rextester.com/GYV10206

返回：

+---------+---------+-----------+------------+------------+-----------+------------+---------+------------+
| Country | Town_01 |  City_01  |  Town_02   |  City_02   |  Town_03  |  City_03   | Town_04 |  City_04   |
+---------+---------+-----------+------------+------------+-----------+------------+---------+------------+
| India   | Bang    | Bangalore | Del        | New Delhi  | hyder     | Hyderabad  | townin  | India Town |
| UK      | chelsea | London    | sunderland | Birmingham | United    | Manchester | NULL    | NULL       |
| USA     | Dally   | Dallas    | houst      | Houston    | New Jersy | New York   | NULL    | NULL       |
+---------+---------+-----------+------------+------------+-----------+------------+---------+------------+

Answer 2

COALESCE是您正在寻找的功能。它将返回第一个非null值。更多信息：

https://docs.microsoft.com/en-us/sql/t-sql/language-elements/coalesce-transact-sql

Answer 3

试试这段代码：

with cte as
(Select Country, min(town1) as town1, min(City1) as City1, min(town2)as town2, min(City2)as City2, min(town3)as town3, 
min(City3) as City3, min(town4) as town4, min(City4) as City4, min(town5) as town5, min(City5) as City5
From
(
Select Country, City, 'City'+ cast(row_number() over(partition by Country order by Country) as varchar(10)) ColumnSequence,
Town, 'Town'+ cast(row_number() over(partition by Country order by Country) as varchar(10)) ColumnSequence2 
from Countries
) Temp
pivot
(
max(City)
for ColumnSequence in (City1, City2, City3, City4, City5) 
) Piv
pivot
(
max(Town)
for ColumnSequence2 in (town1, town2, town3, town4, town5) 
) Piv
group by Country)
Select t.Country, COALESCE(t.town1,d.town1), COALESCE(t.City1,d.city1), COALESCE(t.town2,d.town2), 
COALESCE(t.City2,d.city2), COALESCE(t.town3,d.town3), COALESCE(t.City3,d.city3), COALESCE(t.town4,d.town4), 
COALESCE(t.City4,d.city4), COALESCE(t.town5,d.town5), COALESCE(t.City5,d.city5)
from cte d iNNER JOIN CTE t ON d.country = t.country

旋转多个动态行

3 个答案: