Question

我想在php中发送带有帖子的Json对象。如何发送json对象发布它。我在这里尝试了几个帖子，但它没有用。

这是我试过的代码：

function get_user_post_other_count($user_id, $call_for)
{
    $params = array('user_id' => $user_id,
        'call_for' => $call_for);
// Build Http query using params
    $query = json_encode($params);

// Create Http context details
    $contextData = array(
        'method' => 'POST',
        'header' => 'Content-Type: application/json' . "\r\n" . 'Content-Length: ' . strlen($query) . "\r\n",
        'content' => $query);
    $context = stream_context_create(array('http' => $contextData));
    $result = file_get_contents(USER_PROFILE_COUNTER, false, $context);
    $json_decoded = json_decode($result, true);
    return $json_decoded;
}

Answer 1

$context_options = array (
        'http' => array (
            'method' => 'POST',
            'header'=> "Content-type: application/x-www-form-urlencoded\r\n"
                . "Content-Length: " . strlen($data) . "\r\n",
            'content' => json_encode($data)
            )
        );

$fp = fopen('http://url', 'r', false, $context_options);

Answer 2

使用json和ajax将javascript obj发送到php：

JS：

var dataPost = {
   "var": "foo"
};
var dataString = JSON.stringify(dataPost);

$.ajax({
   url: 'server.php',
   data: {myData: dataString},
   type: 'POST',
   success: function(response) {
      alert(response);
   }
});

在php中使用该对象：

   $obj = json_decode($_POST["myData"]);

    echo $obj->var;

Answer 3

第1步：在您的php文件中添加此功能：

<?php

function do_post($url, $data, $optional_headers = null) {

  $params = ['http' => ['method' => 'POST', 'content' => $data]];

  if ($optional_headers !== null) {
      $params['http']['header'] = $optional_headers;
  }

  $ctx = stream_context_create($params);
  $fp = @fopen($url, 'rb', false, $ctx);

  if (!$fp) {
      throw new Exception("Exception caused with $url, $php_errormsg");
  }

  $response = @stream_get_contents($fp);

  if ($response === false) {
      throw new Exception("Error reading response from $url, $php_errormsg");
  }

  return $response;

}

第2步：相应更改功能

function get_user_post_other_count($user_id, $call_for) {
    $params = array('user_id' => $user_id, 'call_for' => $call_for);    
    $query = json_encode($params);
    $response = do_post($url, $query);

    return json_decode($response, true);
}

我会在这里推荐curl。

Answer 4

使用PHP Curl http://php.net/manual/en/curl.examples.php

$ ch = curl_init（）;

    // set url 
    curl_setopt($ch, CURLOPT_URL, "example.com"); 

    //return the transfer as a string 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 

    // $output contains the output string 
    $output = curl_exec($ch); 

    // close curl resource to free up system resources 
    curl_close($ch);

如何在PHP中发送post json对象？

4 个答案: