如何在具有特定输入单元格值的Web表中查找行

Question

如果我必须发送我的输入字段数组，例如var arr=["Tiger",69,"Edinburgh"]，则jQuery必须能够找到包含name:Tiger Age:69和place:Edinburgh的行。输入数组可以是任何大小，因此应标识Web表中的列和行。

非常感谢任何帮助。提前谢谢！

＆＃13;

＆＃13;

<table id="example" class="display" width="100%">
  <thead>
    <tr>
      <th>Name</th>
      <th>Position</th>
      <th>Office</th>
      <th>Age</th>
      <th>Start date</th>
      <th>Salary</th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td>Tiger</td>
      <td>System Architect</td>
      <td>Edinburgh</td>
      <td>61</td>
      <td>2011/04/25</td>
      <td>$320,800</td>
    </tr>
    <tr>
      <td>Garrett Winters</td>
      <td>Accountant</td>
      <td>Tokyo</td>
      <td>63</td>
      <td>2011/07/25</td>
      <td>$170,750</td>
    </tr>
    <tr>
      <td>Ashton Cox</td>
      <td>Junior Technical Author</td>
      <td>San Francisco</td>
      <td>66</td>
      <td>2009/01/12</td>
      <td>$86,000</td>
    </tr>
    <tr>
      <td>Cedric Kelly</td>
      <td>Senior Javascript Developer</td>
      <td>Edinburgh</td>
      <td>22</td>
      <td>2012/03/29</td>
      <td>$433,060</td>
    </tr>
    <tr>
      <td>Airi Satou</td>
      <td>Accountant</td>
      <td>Tokyo</td>
      <td>33</td>
      <td>2008/11/28</td>
      <td>$162,700</td>
    </tr>
    <tr>
      <td>Brielle Williamson</td>
      <td>Integration Specialist</td>
      <td>New York</td>
      <td>61</td>
      <td>2012/12/02</td>
      <td>$372,000</td>
    </tr>
    <tr>
      <td>Tiger</td>
      <td>System Architect</td>
      <td>Edinburgh</td>
      <td>69</td>
      <td>2011/04/25</td>
      <td>$320,800</td>
    </tr>
    <tr>
      <td>Herrod Chandler</td>
      <td>Sales Assistant</td>
      <td>San Francisco</td>
      <td>59</td>
      <td>2012/08/06</td>
      <td>$137,500</td>
    </tr>
    <tr>
      <td>Rhona Davidson</td>
      <td>Integration Specialist</td>
      <td>Tokyo</td>
      <td>55</td>
      <td>2010/10/14</td>
      <td>$327,900</td>
    </tr>
    <tr>
      <td>Colleen Hurst</td>
      <td>Javascript Developer</td>
      <td>San Francisco</td>
      <td>39</td>
      <td>2009/09/15</td>
      <td>$205,500</td>
    </tr>
    <tr>
      <td>Sonya Frost</td>
      <td>Software Engineer</td>
      <td>Edinburgh</td>
      <td>23</td>
      <td>2008/12/13</td>
      <td>$103,600</td>
    </tr>
    <tr>
      <td>Jena Gaines</td>
      <td>Office Manager</td>
      <td>London</td>
      <td>30</td>
      <td>2008/12/19</td>
      <td>$90,560</td>
    </tr>
  </tbody>
</table>

＆＃13;

＆＃13;

＆＃13;

Answer 1

答案更新

  

如果我发送带有列名和搜索输入的字典，可以解决什么问题。例如：

     

var dict = {“姓名”：“老虎”，“年龄”：69};

根据您的评论，我建议您提供以下解决方案：

• 从dict元素计算相应的表col索引
每个表行的
• ：测试每个元素是否满足所有条件

//
// let's assume we are looking for:
//
var dict={"Name":"Tiger","Age":69};

//
// Let's create the correspondence betwen column name and column index
//
var colIdx = {};

$('#example thead tr th').filter(function(idx, ele) {
   var keyName = ele.textContent;
    var keyValue = Object.keys(dict).indexOf(keyName);
    if (keyValue != -1) {
        colIdx[keyName] = idx;
    }
});

//
// For each table row in the body section
//
var colIndexes = Object.keys(colIdx);
$('#example tbody tr').filter(function(idx, ele) {
    var fVal = colIndexes.filter(function(colName, idx) {
        var colValue = dict[colName];
        var colIndex = colIdx[colName];
        return ($(ele).find('td').eq(colIndex).text() == colValue)
    });
    // if all conditions are satisfied...
    return fVal.length == colIndexes.length;
}).css('background-color', 'red')

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<table id="example" class="display" width="100%">
    <thead>
    <tr>
        <th>Name</th>
        <th>Position</th>
        <th>Office</th>
        <th>Age</th>
        <th>Start date</th>
        <th>Salary</th>
    </tr>
    </thead>
    <tbody>
    <tr>
        <td>Tiger</td>
        <td>System Architect</td>
        <td>Edinburgh</td>
        <td>61</td>
        <td>2011/04/25</td>
        <td>$320,800</td>
    </tr>
    <tr>
        <td>Garrett Winters</td>
        <td>Accountant</td>
        <td>Tokyo</td>
        <td>63</td>
        <td>2011/07/25</td>
        <td>$170,750</td>
    </tr>
    <tr>
        <td>Ashton Cox</td>
        <td>Junior Technical Author</td>
        <td>San Francisco</td>
        <td>66</td>
        <td>2009/01/12</td>
        <td>$86,000</td>
    </tr>
    <tr>
        <td>Cedric Kelly</td>
        <td>Senior Javascript Developer</td>
        <td>Edinburgh</td>
        <td>22</td>
        <td>2012/03/29</td>
        <td>$433,060</td>
    </tr>
    <tr>
        <td>Airi Satou</td>
        <td>Accountant</td>
        <td>Tokyo</td>
        <td>33</td>
        <td>2008/11/28</td>
        <td>$162,700</td>
    </tr>
    <tr>
        <td>Brielle Williamson</td>
        <td>Integration Specialist</td>
        <td>New York</td>
        <td>61</td>
        <td>2012/12/02</td>
        <td>$372,000</td>
    </tr>
    <tr>
        <td>Tiger</td>
        <td>System Architect</td>
        <td>Edinburgh</td>
        <td>69</td>
        <td>2011/04/25</td>
        <td>$320,800</td>
    </tr>
    <tr>
        <td>Herrod Chandler</td>
        <td>Sales Assistant</td>
        <td>San Francisco</td>
        <td>59</td>
        <td>2012/08/06</td>
        <td>$137,500</td>
    </tr>
    <tr>
        <td>Rhona Davidson</td>
        <td>Integration Specialist</td>
        <td>Tokyo</td>
        <td>55</td>
        <td>2010/10/14</td>
        <td>$327,900</td>
    </tr>
    <tr>
        <td>Colleen Hurst</td>
        <td>Javascript Developer</td>
        <td>San Francisco</td>
        <td>39</td>
        <td>2009/09/15</td>
        <td>$205,500</td>
    </tr>
    <tr>
        <td>Sonya Frost</td>
        <td>Software Engineer</td>
        <td>Edinburgh</td>
        <td>23</td>
        <td>2008/12/13</td>
        <td>$103,600</td>
    </tr>
    <tr>
        <td>Jena Gaines</td>
        <td>Office Manager</td>
        <td>London</td>
        <td>30</td>
        <td>2008/12/19</td>
        <td>$90,560</td>
    </tr>
    </tbody>
</table>