Question

我有一个像这样的表结构中的表：

[1] = {
    [1] = {
        category = "WORD",
        cursor = <filtered>,
        ptype = "STATEMENT",
        ttype = "SERVICE",
        value = "service",
        <metatable> = <filtered>
    },
    [2] = {
        category = "VARIABLE",
        cursor = <filtered>,
        ptype = "STATEMENT",
        ttype = "IDENTIFIER",
        value = "TestService",
        <metatable> = <filtered>
    },
    [3] = {
        ttype = "BRACE_BLOCK",
        value = {
            [1] = { ...
...
[2] = {
    [1] = {
        category = "WORD",
        cursor = <filtered>,
        ptype = "STATEMENT",
        ttype = "SERVICE",
        value = "service",
        <metatable> = <filtered>
    },
    [2] = {
        category = "VARIABLE",
        cursor = <filtered>,
        ptype = "STATEMENT",
        ttype = "IDENTIFIER",
        value = "HelloWorld",
        <metatable> = <filtered>
    },

我编写了一个简单的循环，它查找带有ttype的第一个表，过滤掉该信息并希望分配其余的标记，直到下一个服务开始相应的服务。我的想法看起来像那样：

 local found_service = 0
 if found_service == 0 then
 for k1, v1 in pairs (parse_tree) do
      for i=1,#v1 do
            if v1[i].ttype == "SERVICE"  then
            --Store wanted data in an object
             found_service = 1
             end  
            if (found_service == 1 and v1[i].ttype ~= "SERVICE") then
            -- ->assign the rest to last found service
            end
            if found_service == 1 and v1[i].ttype == "SERVICE" then
            -- ->Found the next service -->starting over
            found_service = 0
            end
        end    
   end
 end

问题是我坚持索引i，而v1 [i]是＆＃34; SERVICE＆＃34;，所以他也直接输入了最后一个if子句。如何结束一次循环迭代（在第一个if子句之后）。或者有更好的方法吗？

谢谢你的建议。西奥

Answer 1

我不确定我是否理解你的一般想法，但这里是如何在第一次"SERVICE"捕获事件中跳过循环体的答案。

 local found_service = 0
 if found_service == 0 then
 for k1, v1 in pairs (parse_tree) do
      for i=1,#v1 do
            if (found_service == 0 and v1[i].ttype == "SERVICE")  then
                --Store wanted data in an object
                found_service = 1
            else
                if (found_service == 1 and v1[i].ttype ~= "SERVICE") then
                    -- ->assign the rest to last found service
                end
                if found_service == 1 and v1[i].ttype == "SERVICE" then
                    -- ->Found the next service -->starting over
                    found_service = 0
                end
             end  
        end    
   end
 end

但我仍然不明白应该对当前记录做什么，而不是"SERVICE"和found_service == 0。顺便说一下，在found_service在第三个if中变为0之后的答案中，第一个if可能再次为true。

如果您的想法是构建某种类型的向量，例如：
SERVICE_1（其他ttype表，直到下一个SERVICE）
SERVICE_2（其他ttype表，直到下一个SERVICE）
......

在这种情况下，代码可以是：

 local found_service = 0
 if found_service == 0 then
 for k1, v1 in pairs (parse_tree) do
      for i=1,#v1 do
            if (found_service == 0 and v1[i].ttype == "SERVICE")  then
                --Store wanted data in an object
                found_service = 1
                current_service = v1[i]
            else
                if (found_service == 1 and v1[i].ttype ~= "SERVICE") then
                    -- ->assign the rest to last found service
                end
                if found_service == 1 and v1[i].ttype == "SERVICE" then
                    -- ->Found the next service -->starting over
                    current_service = v1[i]
                end
             end  
        end    
   end
 end

在表lua中搜索表

1 个答案: