Question

我有以下课程，可以创建一副牌：

import collections


Card = collections.namedtuple('Card', ['rank', 'suit', 'value'])


class FrenchDeck:
    ranks = [str(n) for n in range(2, 11)] + list('JQKA')
    suits = 'spades clubs hearts diamonds'.split()
    card_value = [str(n + 1) for n in range(len(ranks))]

    def __init__(self):
        self._cards = [Card(rank, suit, value)
                       for suit in self.suits
                       for rank in self.ranks
                       for value in self.card_value
                       ]

    def __len__(self):
        return len(self._cards)

    def __getitem__(self, position):
        return self._cards[position]

if __name__ == '__main__':
    FrenchDeck()

我已将value值添加到卡片中，以便为每张卡片分配一个值，如下所示：

Card(rank='2', suit='spades', value='1')
Card(rank='2', suit='spades', value='2')
Card(rank='2', suit='spades', value='3')
Card(rank='2', suit='spades', value='4')
Card(rank='2', suit='spades', value='5')
Card(rank='2', suit='spades', value='6')
Card(rank='2', suit='spades', value='7')
Card(rank='2', suit='spades', value='8')
Card(rank='2', suit='spades', value='9')
Card(rank='2', suit='spades', value='10')
Card(rank='2', suit='spades', value='11')
Card(rank='2', suit='spades', value='12')
Card(rank='2', suit='spades', value='13')

每件套装为每个等级创造13件物品。我理解为什么会发生这种情况但是我正在努力为这样的西装中的每个等级增加价值：

Card(rank='2', suit='spades', value='1')
Card(rank='3', suit='spades', value='2')
Card(rank='4', suit='spades', value='3')
Card(rank='5', suit='spades', value='4')
Card(rank='6', suit='spades', value='5')
Card(rank='7', suit='spades', value='6')
Card(rank='8', suit='spades', value='7')
Card(rank='9', suit='spades', value='8')
Card(rank='10', suit='spades', value='9')
Card(rank='J', suit='spades', value='10')
Card(rank='K', suit='spades', value='11')
Card(rank='Q', suit='spades', value='12')
Card(rank='A', suit='spades', value='13')

知道如何实现这个目标吗？

Answer 1

你实际上没有像你想象的那样嵌套你的列表迭代。

从

改变

def __init__(self):
    self._cards = [Card(rank, suit, value)
                   for suit in self.suits
                   for rank in self.ranks
                   for value in self.card_value
                   ]

到

def __init__(self):
    self._cards = [Card(rank, suit, value)
                   for suit in self.suits
                   for rank, value in zip(self.ranks,\
                                          self.card_value)
                   ]

完成你想要的。请注意，这相当于：

def __init__(self):
    self._cards = []
    for suit in self.suits:
        for rank, value in zip(self.ranks, self.card_value):            
            self._cards+=[Card(rank, suit, value)]

此外，正如chepner所说，或由Jérémy操作，

value不是Card的独立属性;它是rank。
的函数

这意味着您可以value self.card_value self.suits为rank的每个元素，然后根据value得到相应的ranks工作。

Python - 如何使用列表推导来填充命名的元组值

2 个答案:

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