Question

我正在尝试选择selected中的选项。在我的代码中，每个用户都给彼此分数。我尝试过一些东西，但它不起作用。如果所选值等于给予用户的等级，则该选项应保持选中状态。我使用AbstractUser这就是User = get_user_model()的原因，但我决定不显示它，因为它没用。

models.py

class Score(models.Model):
    VALUE = (
        (1, "Score 1"),
        (2, "Score 2"),
        (3, "Score 3"),
        (4, "Score 4"),
        (5, "Score 5"),
        (6, "Score 6"),
        (7, "Score 7"),
        (8, "Score 8"),
        (9, "Score 9"),
        (10, "Score 10"),
    )
    granted_by = models.ForeignKey(settings.AUTH_USER_MODEL, default=0)
    granted_to = models.ForeignKey(settings.AUTH_USER_MODEL, default=0, related_name='granted_to')
    grade = models.PositiveSmallIntegerField(default=0, choices=VALUE)

    def __str__(self):
        return str(self.granted_to)

views.py

@login_required(login_url='/login/')
def vote(request):
    User = get_user_model()
    data = dict()
    data['users'] = User.objects.exclude(username=request.user)
    if request.method == "POST":
        if "rating" in request.POST:
            for key in request.POST:
                if 'grade_' in key:
                    awarded_grade = Score.objects.filter(granted_by=request.user,
                                                       granted_to__id=key.split('_')[1]).first()
                    if awarded_grade:
                        awarded_grade.grade = request.POST.get(key)
                        awarded_grade.save()
                    else:
                        Score.objects.create(granted_by=request.user,
                                               granted_to_id=key.split('_')[1],
                                               grade=request.POST.get(key))
    data['values'] = Score.VALUE
    data['grade'] = Score.objects.filter(granted_by=request.user)
    return render(request, 'vote.html', data)

vote.html

{% for user in users %}
    <tr>
        <td>{{ user.date_joined|date:"d.m.Y H:i" }}</td>
        <td>{{ user.username }} </td>
        <td>{{ user.id }}</td>
        <td>
            <select title="selecting_grade" name="grade_{{ user.id }}">
                {% for value in values %}
                    <option value="{{ value.0 }}" {% for a in grades %} {% if a.grade == value.0 %}selected{% endif %} {% endfor %} >{{ value.0 }}</option>
                {% endfor %}
            </select>
        </td>
    </tr>
{% endfor %}

我在控制台中试过这样的东西：

user_grade = Score.objects.filter(granted_by__username='Stalone', granted_to__username='Fane')
user_grade
<QuerySet [<Score: Fane>]>

for x in granted_user:
    print(x.grade)

2

或：

a = CustomUser.objects.all()
for user in a:
    grades = user.granted_to.values()
    print(grades)
<QuerySet [{'id': 22, 'grade': 5, 'granted_to_id': 14, 'granted_by_id': 1}]>
<QuerySet [{'id': 21, 'grade': 5, 'granted_to_id': 15, 'granted_by_id': 1}]>
<QuerySet [{'id': 19, 'grade': 5, 'granted_to_id': 16, 'granted_by_id': 1}]>
<QuerySet [{'id': 23, 'grade': 7, 'granted_to_id': 17, 'granted_by_id': 1}]>
<QuerySet [{'id': 20, 'grade': 8, 'granted_to_id': 18, 'granted_by_id': 1}]>
<QuerySet [{'id': 24, 'grade': 7, 'granted_to_id': 19, 'granted_by_id': 1}]>

为了看看我是否可以获得给每个用户的分数并在选中使用它们，我得到了它们，但我没有设法使用它们，有什么建议吗？

Answer 1

在views.py中，您传递了grade

data['grade'] = Score.objects.filter(granted_by=request.user)

但是在vote.html中，您正在使用grades

进行迭代

<option value="{{ value.0 }}" {% for a in grades %} {% if a.grade == value.0 %}selected{% endif %} {% endfor %} >{{ value.0 }}</option>

将grade更改为grades中的views.py或将grades更改为grade中的vote.html

Django，无法选择选项

1 个答案: