php mysql从json中的mulitiple表中获取数据

Question

请帮助，我需要从两个表中获取数据，并在json我的表中编码

1. Customers_table

  

id | inv_id | customer_name |地址| total_value

1. Items_table

  

id | inv_id |描述|细节|数量| UNIT_PRICE

我的PHP代码如下：

<?php
require "config.php";

$sql = "SELECT customers_table.id,
                customers_table.inv_id,
                customers_table.customer_name,
                customers_table.address,
                customers_table.total_value,
                items_table.inv_id,
                items_table.description,
                items_table.details,
                items_table.inv_id,
                items_table.qty,
                items_table.ubit_price,
                items_table.amount,

                FROM customers_table INNER JOIN items_table ON
                customers_table.inv_id = items_table.inv_id;";
$result = mysqli_query($db, $sql);
$response = array();

while ($row = mysqli_fetch_array($result))
    {
    array_push($response);
    }

echo json_encode(array(
    "server_response" => $response
));
mysqli_close($db)
?>

但是JSONLint响应是

{
    "server_response": []
}

请问，我做错了什么？

Answer 1

array_push()接受两个参数，例如array_push($array, $element_to_be_pushed)。 array_push reference

您可以使用$array[]重写相同的代码，这会将新元素推送到下一个可用的索引。

试用此代码：

<?php
require "config.php";
$sql ="SELECT customers_table.id,
                customers_table.inv_id,
                customers_table.customer_name,
                customers_table.address,
                customers_table.total_value,
                items_table.inv_id,
                items_table.description,
                items_table.details,
                items_table.inv_id,
                items_table.qty,
                items_table.ubit_price,
                items_table.amount
                FROM customers_table INNER JOIN items_table ON
                customers_table.inv_id = items_table.inv_id;";
$result = mysqli_query($db, $sql);

$response = array();

while($row = mysqli_fetch_array($result))
{
    $response[] = $row;
}
echo json_encode(array("server_response"=> $response));
mysqli_close($db)
?>

更新回答：

额外的逗号“items_table.amount,”已删除。