任何人都可以帮助我添加基本工资和津贴I,并将其插入总日费率而无需单击按钮。这是我的PHP代码 这是我的用户界面Screen Shot 代码:
<?php
$connection = mysql_connect("localhost", "root", "");
$db = mysql_select_db("laboursalary", $connection);
if(isset($_POST['submit'])){
$ID = $_POST['ID'];
$Name = $_POST['Name'];
$Location = $_POST['Location'];
$Category = $_POST['Category'];
$LabourSupplier = $_POST['LabourSupplier'];
$Home = $_POST['Home'];
$Mobile = $_POST['Mobile'];
$BasicSalary = $_POST['BasicSalary'];
$Allowance1 = $_POST['Allowance1'];
$Allowance2 = $_POST['Allowance2'];
$DayRate = $_POST['$DayRate'];
$OTrate = $_POST['OTrate'];
if($ID !=''||$Name !=''){
$query = mysql_query("insert into attendance(ID, Name, Location, Category,LabourSupplier,Home,Mobile,BasicSalary,Allowance1,Allowance2,DayRate,OTrate) values ('$ID','$Name','$Location','$Category','$LabourSupplier','$Home','$Mobile','$BasicSalary','$Allowance1','$Allowance2','$DayRate','$OTrate')");
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
}
else{
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}
mysql_close($connection);
?>
输入基本工资和津贴1的值后,我想自动在日费率中添加这两个。
这是我的 HTML 代码。
<form id="details" action="" method="POST">
<fieldset> ID:
<input class="input" type="text" name="ID" value="" />
</fieldset>
<fieldset> Name:
<input class="input" type="text" name="Name" value="" />
</fieldset>
<fieldset> Location:
<input class="input" type="text" name="Location" value="" />
</fieldset>
<fieldset> Category:
<input class="input" type="text" name="Category" value="" />
</fieldset>
<fieldset> Labour Supplier:
<input class="input" type="text" name="LabourSupplier" value="" />
</fieldset>
<fieldset> Telephone:
<input class="input" type="text" name="Home" value="" />
</fieldset>
<fieldset>Mobile:
<input class="input" type="text" name="Mobile" value="" />
</fieldset>
<fieldset> Basic Salary:
<input class="input" type="number" name="BasicSalary" value="" />
</fieldset>
<fieldset> Allowance I:
<input class="input" type="number" name="Allowance1" value="" />
</fieldset>
<fieldset>Allowance II:
<input class="input" type="number" name="Allowance2" value="" />
</fieldset>
<fieldset>Total Day Rate:
<input class="input" type="number" name="DayRate" value="" />
</fieldset>
<fieldset>OT Rate:
<input class="input" type="number" name="OTrate" value="" />
</fieldset>
<fieldset>
<button name="submit" type="submit" id="submit">Insert</button>
<button onclick="goBack()" name="Back" type="back" id="details-back">Back</button>
</fieldset>
</form>
答案 0 :(得分:0)
这就是使用提交发布的方式,因为这些都是_POST值...虽然没有按下按钮就可以实现这一点,但JS / Angular / J Query / AJAX ......
....
$BasicSalary = $_POST['BasicSalary'];
$Allowance1 = $_POST['Allowance1'];
$Allowance2 = $_POST['Allowance2'];
$DayRate = $_POST['$DayRate'];
$OTrate = $_POST['OTrate'];
//Set a new variable with the addition of the two `Basic Salary` and `Allowance 1`
//for the insertion into your column `dayRate`
$adustedDayRate = $BasicSalary + $Allowance1;
if($ID !=''||$Name !=''){
if($query != false){
$query = mysql_query("INSERT INTO `attendance` (ID, Name, Location, Category,LabourSupplier,Home,Mobile,BasicSalary,Allowance1,Allowance2,DayRate,OTrate) values ('$ID','$Name','$Location','$Category','$LabourSupplier','$Home','$Mobile','$BasicSalary','$Allowance1','$Allowance2','$adustedDayRate','$OTrate')");
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
}esle{ $_SESSION['err'] = "ERROR: ".--- MySQL error handle here --- }
}
else{
echo "Some Fields are Blank....!!</p>";
}
}
mysql_close($connection);
使用Angular ,您可以在“DayRate”的表单输入中放置占位符元素,然后为要添加的两个输入的ng-model元素添加回调。这里有类似的东西:
<div ng-app="">
<p>BasicSalary : <input type="number" ng-model="BasicSalary" placeholder="Basic Salary"></p>
<p>AllowanceI : <input type="number" ng-model="AllowanceI" placeholder="Allowance I"></p>
<p>DayRate : <input type="number" ng-model="DayRate" placeholder="{{BasicSalary -- AllowanceI}}"></p>
您的代码如下:
<fieldset> Basic Salary:
<input class="input" type="number" ng-model="BasicSalary" name="BasicSalary" value="" />
</fieldset>
<fieldset> Allowance I:
<input class="input" type="number" ng-model="Allowance1" name="Allowance1" value="" />
</fieldset>
<fieldset>Allowance II:
<input class="input" type="number" name="Allowance2" value="" />
</fieldset>
<fieldset>Total Day Rate:
<input class="input" type="number" name="DayRate" placeholder="{{ BasicSalary -- Allowance1 }}" value="" />
</fieldset>
这是一个角度方法的工作小提琴,只需使用composer或托管链接将角度库添加到服务器,Angular库元素不需要额外的JS。您可以在输入另外两个组合输入时更改DayRate的值。 https://jsfiddle.net/qkpfb90o/1/
希望这有帮助!
答案 1 :(得分:0)
据我了解您的问题,您的 HTML 代码应该是,
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
</head>
<body>
<form id="details" action="" method="POST">
<fieldset> ID:
<input class="input" type="text" name="ID" value="" />
</fieldset>
<fieldset> Name:
<input class="input" type="text" name="Name" value="" />
</fieldset>
<fieldset> Location:
<input class="input" type="text" name="Location" value="" />
</fieldset>
<fieldset> Category:
<input class="input" type="text" name="Category" value="" />
</fieldset>
<fieldset> Labour Supplier:
<input class="input" type="text" name="LabourSupplier" value="" />
</fieldset>
<fieldset> Telephone:
<input class="input" type="text" name="Home" value="" />
</fieldset>
<fieldset>Mobile:
<input class="input" type="text" name="Mobile" value="" />
</fieldset>
<fieldset> Basic Salary:
<input class="input" type="number" name="BasicSalary" value="0" id="bassal" />
</fieldset>
<fieldset> Allowance I:
<input class="input" type="number" name="Allowance1" value="0" id="all1" />
</fieldset>
<fieldset>Allowance II:
<input class="input" type="number" name="Allowance2" value="0" id="all2" />
</fieldset>
<fieldset>Total Day Rate:
<input class="input" type="number" name="DayRate" value="" id="DayRate" />
</fieldset>
<fieldset>OT Rate:
<input class="input" type="number" name="OTrate" value="" />
</fieldset>
<fieldset>
<button name="submit" type="submit" id="submit">Insert</button>
<button onclick="goBack()" name="Back" type="back" id="details-back">Back</button>
</fieldset>
</form>
<script >
$(document).ready(function (){
$('#bassal').on('input', function() {
$('#DayRate').val(parseInt($('#bassal').val()) + parseInt($("#all1").val()) + parseInt($("#all2").val()));
});
$('#all1').on('input', function() {
$('#DayRate').val(parseInt($('#bassal').val()) + parseInt($("#all1").val()) + parseInt($("#all2").val()));
});
$('#all2').on('input', function() {
$('#DayRate').val(parseInt($('#bassal').val()) + parseInt($("#all1").val()) + parseInt($("#all2").val()));
});
});
</script>
我添加了jQuery,它可以完成你的工作,而且你不需要在PHP端添加。
答案 2 :(得分:0)
你也可以试试这个。
<form id="details" action="" method="POST">
<fieldset> ID:
<input class="input" type="text" name="ID" value="" />
</fieldset>
<fieldset> Name:
<input class="input" type="text" name="Name" value="" />
</fieldset>
<fieldset> Location:
<input class="input" type="text" name="Location" value="" />
</fieldset>
<fieldset> Category:
<input class="input" type="text" name="Category" value="" />
</fieldset>
<fieldset> Labour Supplier:
<input class="input" type="text" name="LabourSupplier" value="" />
</fieldset>
<fieldset> Telephone:
<input class="input" type="text" name="Home" value="" />
</fieldset>
<fieldset>Mobile:
<input class="input" type="text" name="Mobile" value="" />
</fieldset>
<fieldset> Basic Salary:
<input class="input" type="number" name="BasicSalary" value="" id="BasicSalary" onkeyup="doSum()"/>
</fieldset>
<fieldset> Allowance I:
<input class="input" type="number" name="Allowance1" value="" id="Allowance1" onkeyup="doSum()"/>
</fieldset>
<fieldset>Allowance II:
<input class="input" type="number" name="Allowance2" />
</fieldset>
<fieldset>Total Day Rate:
<input class="input" type="number" name="DayRate" value="" id="DayRate" />
</fieldset>
<fieldset>OT Rate:
<input class="input" type="number" name="OTrate" value="" />
</fieldset>
<fieldset>
<button name="submit" type="submit" id="submit">Insert</button>
<button onclick="goBack()" name="Back" type="back" id="details-back">Back</button>
</fieldset>
<script>
function doSum() {
var Allowance1 = isNaN(document.getElementById('Allowance1').value) ? document.getElementById('Allowance1').value : 0;
var BasicSalary = isNaN(document.getElementById('BasicSalary').value) ? document.getElementById('BasicSalary').value : 0;
var tot = parseInt(Allowance1) + parseInt(BasicSalary);
document.getElementById('DayRate').value = tot;
}
</script>