Question

这是针对Oracle服务器上的数据运行的MYSQL / SQL。我有一个SQL表，存储数据如下：

{IMPORTID Created  IMPORTREQUESTID    STARTDATE       ENDDATE
1156     04/21/2017 (12 AM)    63833           4/23/2017 18:18 4/23/2017 18:19
1156     04/21/2017 (12 AM)    63833           4/23/2017 18:18 4/23/2017 18:18
1156     04/21/2017 (12 AM)   63832           4/23/2017 17:56 4/23/2017 17:57
1156     04/21/2017 (12 AM)    63832           4/23/2017 17:56 4/23/2017 17:57
1156     04/21/2017 (12 AM)   63832           4/23/2017 17:56 4/23/2017 17:57}

我希望查询遍历表格并找到任何给定IMPORTID的HIGHEST或MAX IMPORTREQUESTID和最大ENDDATE。然后，一旦找到包含最大值的行，就计算任何给定IMPORTID的CREATED和max（ENDDATE）之间的差异。同样，我只想将最大IMPORTREQUESTID和ENDDATE绑定到给定的IMPORTID。（IMPORTID将有几行具有不同的IMPORTREQUESTIDS）

因此，对于上面给定的数据，我的查询应该只返回1行，如下所示：

{IMPORTID Created  IMPORTREQUESTID    STARTDATE       ENDDATE         DIFF
1156    04/21/2017 12 AM    63833  4/23/2017 18:18  4/23/2017 18:19  **6:19**}

因此，在这种情况下，它发现IMPORTREQUESTID 63833是最高值，而18:19的最终结束时间最长。然后它选择了该行并计算了created和ENDDATE之间的差异。

这是我到目前为止的查询：

     SELECT ImportID 
 ,A.created
 ,IMPORTSTATUS 
 ,IMPORTCANONICALTYPE  
 , to_char(StartDate,'MM/DD/YYYY HH24:MI') StartDate 
 , to_char(EndDate,'MM/DD/YYYY HH24:MI') EndDate  
 , ((A.created-A.Enddate)*60*24) as MinDiff 
 , ImportRequestID

FROM (SELECT DISTINCT importrequestpartdone.ImportID
,importrequestpartdone.IMPORTCANONICALTYPE 
 ,importrequestpartdone.IMPORTSTATUS 
 ,importrequestpartdone.ImportRequestID 
 , importrequestpartdone.StartDate 
 , importrequestpartdone.EndDate 
,import.created
     From import,baywatchnosnap.importrequestpartdone@db1 
 where contextid=10114
and import.id=importrequestpartdone.importid
and importrequestpartdone.importstatus='2I') A

返回所有行。我只想要如上所示的最大值。因此，每个IMPORTID应该只返回1行。

Answer 1

即使我不明白你是如何达到6:19的差异，因为差异仅为1分钟

但试试这个： -

SELECT importrequestpartdone.ImportID 
 ,import.created
 ,importrequestpartdone.IMPORTSTATUS 
 ,importrequestpartdone.IMPORTCANONICALTYPE  
 , to_char(StartDate,'MM/DD/YYYY HH24:MI') StartDate 
 , to_char(EndDate,'MM/DD/YYYY HH24:MI') EndDate  
 , ((A.created-A.Enddate)*60*24) as MinDiff 
 , importrequestpartdone.ImportRequestID

FROM baywatchnosnap.importrequestpartdone@db1
inner join

(SELECT importrequestpartdone.ImportID
 ,max(importrequestpartdone.ImportRequestID) as max_req_id
 , max(importrequestpartdone.EndDate) as max_end
     From import,baywatchnosnap.importrequestpartdone@db1  
 where contextid=10114
and import.id=importrequestpartdone.importid
and importrequestpartdone.importstatus='2I'
group by importrequestpartdone.ImportID ) A

on a.ImportID=importrequestpartdone.ImportID and a.max_req_id=importrequestpartdone.ImportRequestID
and a.max_end=importrequestpartdone.EndDate

inner join
import
on import.id=importrequestpartdone.importid
where contextid=10114
and importrequestpartdone.importstatus='2I';

按最高/最大值分组并计算差异

1 个答案: