Question

寻求我的功能帮助...

该功能试图帮助用户将他们选择的主题的选择添加到列表中。它应该询问用户他们想要输入多少选择。必须至少有2个，但如果用户输入的数字> 2，我希望该函数能够为用户生成适当数量的提示输入总选项 - 2（因为该函数假设最少为2），然后继续将输入附加到同一列表中，一旦用户输入所有输入，该列表将在最后返回。我在最后一部分遇到了问题：＆＃34;如果数字> 2 ...＆＃34;我不知道如何调用choice.append（输入（...））数字 - 2次。任何帮助将不胜感激！

def first_decisions2():   
    number = int((input("Please enter the number of deciding options (eg. 2 or 
    greater): ")))
    choice = []
    if number <2:
        return "I'm sorry - you didn't enter enough criteria. Please try again."
    if number == 2:
        choice.append(input("Please enter the first choice: ")),
        choice.append(input("Please enter the second choice: "))
        return choice

    if number >2:
        return (number - 2) * choice.append(input("Please enter the next choice: "))

    return choice

Answer 1

def first_decisions2():   
    number = int((input("Please enter the number of deciding options (eg. 2 or greater): ")))
    choice = []
    if number < 2:
        # return "I'm sorry - you didn't enter enough criteria. Please try again."
        return false

    if number == 2:
        choice.append(input("Please enter the first choice: ")),
        choice.append(input("Please enter the second choice: "))
        return choice

    if number > 2:
        for c in range(0, number - 1):
            choice.append(input("Please enter the next choice: "))
        return choice

    return choice

我会遍历所选择的数字，每次都要求输入

是否可以在函数中乘以append.input？

1 个答案: