Question

我已阅读有关此错误的多篇帖子，但我仍然无法弄明白。当我尝试循环我的函数时：

def fix_Plan(location):
    letters_only = re.sub("[^a-zA-Z]",  # Search for all non-letters
                          " ",          # Replace all non-letters with spaces
                          location)     # Column and row to search    

    words = letters_only.lower().split()     
    stops = set(stopwords.words("english"))      
    meaningful_words = [w for w in words if not w in stops]      
    return (" ".join(meaningful_words))    

col_Plan = fix_Plan(train["Plan"][0])    
num_responses = train["Plan"].size    
clean_Plan_responses = []

for i in range(0,num_responses):
    clean_Plan_responses.append(fix_Plan(train["Plan"][i]))

这是错误：

Traceback (most recent call last):
  File "C:/Users/xxxxx/PycharmProjects/tronc/tronc2.py", line 48, in <module>
    clean_Plan_responses.append(fix_Plan(train["Plan"][i]))
  File "C:/Users/xxxxx/PycharmProjects/tronc/tronc2.py", line 22, in fix_Plan
    location)  # Column and row to search
  File "C:\Users\xxxxx\AppData\Local\Programs\Python\Python36\lib\re.py", line 191, in sub
    return _compile(pattern, flags).sub(repl, string, count)
TypeError: expected string or bytes-like object

Answer 1

正如你在评论中所说，一些值似乎是浮点数，而不是字符串。在将其传递给re.sub之前，您需要将其更改为字符串。最简单的方法是在使用location时将str(location)更改为re.sub。即使它已经是str，也不会有任何影响。

letters_only = re.sub("[^a-zA-Z]",  # Search for all non-letters
                          " ",          # Replace all non-letters with spaces
                          str(location))

Answer 2

我想更好的方法是使用re.match（）函数。这是一个可能对您有帮助的示例。

import re
import nltk
from nltk.tokenize import word_tokenize
nltk.download('punkt')
sentences = word_tokenize("I love to learn NLP \n 'a :(")
#for i in range(len(sentences)):
sentences = [word.lower() for word in sentences if re.match('^[a-zA-Z]+', word)]  
sentences

Answer 3

最简单的解决方案是将python str函数应用于您要遍历的列。

如果您使用的是熊猫可以实现为

dataframe ['column_name'] = dataframe ['column_name']。apply（str）

Answer 4

我遇到了同样的问题。而且很有趣的是，每次我做某事，直到我意识到字符串中有两个特殊字符时，问题才解决。

例如，对我来说，文字有两个字符：

&lrm; _{(Left-to-Right Mark)} 和 &zwnj; _{(Zero-width non-joiner)}

我的解决办法是删除这两个字符，问题解决了。


    import re
    mystring = "&lrm;Some Time W&zwnj;e"
    mystring  = re.sub(r"&lrm;","",mystring)
    mystring  = re.sub(r"&zwnj;","",mystring)

我希望这能帮助像我这样有问题的人。

re.sub错误与“预期字符串或字节类对象”

4 个答案: