Question

我正在做一个简单的时钟，它在到达0时回绕（例如00:59 - > 01：00,23：59 - > 00:00）。我此刻陷入困境，无法弄明白。我必须这样做，只使用＆＃39; BoundedCounter＆＃39;中给出的方法。类。

public class Test3 {

    public static void main(String[] args) {

        BoundedCounter minutes = new BoundedCounter(59, 0);
        BoundedCounter hours = new BoundedCounter(23, 0);

        int i = 0;

        while (i < 70) { //repeats actual time 70 times - just to check if works fine

            //put code here
            i++;
        }

    }

}

import java.text.DecimalFormat;

public class BoundedCounter {

private int startValue;
private int upperLimit;
private int value;

public BoundedCounter(int upperLimit, int startValue) {
    this.upperLimit = upperLimit;
    this.startValue = startValue;
    this.value = startValue;
}

public void next() {

    value++;
    if (value > upperLimit) {
        value = 0;
    }
}

public String toString() {
    DecimalFormat df = new DecimalFormat("#00");
    return "" + df.format(value);
    }
}

Answer 1

也许这会有所帮助...显示当前时间：

System.out.println(hours.toString() + ":" + minutes.toString());

增加小时数：hours.next()

增加分钟数：minutes.next()

Answer 2

一种变体是使用处理程序：

import java.text.DecimalFormat;

public class Test3 {
    public static void main(String[] args) {
        final BoundedCounter minutes = new BoundedCounter(59, 0);
        final BoundedCounter hours = new BoundedCounter(23, 0);

        minutes.setOverflow(hours::next);
        hours.setOverflow(minutes::reset);

        for (int i = 0; i < 70; i++) { //repeats actual time 70 times - just to check if works fine
            minutes.next();
            System.out.println(hours.toString() + ":" + minutes.toString());
        }
    }

    public static class BoundedCounter {
        private int startValue;
        private int upperLimit;
        private int value;
        private Runnable c;

        public BoundedCounter(int upperLimit, int startValue) {
            this.upperLimit = upperLimit;
            this.startValue = startValue;
            this.value = startValue;
        }

        public void reset() {
            this.value = startValue;
        }

        public void setOverflow(final Runnable c) {
            this.c = c;
        }

        public void next() {
            if (++value > upperLimit) {
                value = 0;
                c.run();
            }
        }

        public String toString() {
            DecimalFormat df = new DecimalFormat("#00");
            return "" + df.format(value);
        }
    }
}

几分钟到几个小时

2 个答案: