Question

我希望获得每个字符串行的（第一个）价格，而不是$符号，它可以是一个int或float，并且行中可能有更多数字。

示例：

$str_array=(
"Up to $1.9 per Install in RU",
"1.3 per iOS Install in UAE and SA",
"$2.1 per iOS and Android Registration in US",
"Up to $2.5 per Android Install in 7 countries",
"Up to $1 per iOS Install in SA"
);

预期输出：

1.9
1.3
2.1
2.5
1

我试过这样的事情

$re = '/[+-]?([0-9]*[.])?[0-9]+/';
$str = 'Up to $2.5 per Android Install in 7 countries';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
var_dump($matches);

我得到了这个

[0] => Array
    (
        [0] => 2.5
        [1] => 2.
    )

[1] => Array
    (
        [0] => 7
    )

但它不能正常工作。：（

Answer 1

这是我的版本：

<?php
$data = [
    'Up to $1.9 per Install in RU',
    '1.3 per iOS Install in UAE and SA',
    '$2.1 per iOS and Android Registration in US',
    'Up to $2.5 per Android Install in 7 countries',
    'Up to $1 per iOS Install in SA'
];

array_walk($data, function(&$line){
    preg_match('/(\d+(?:\.\d+)?)/', $line, $tokens);
    if (count($tokens)>1) {
        var_dump(floatval($tokens[1]));
    }
});

输出显然是：

float(1.9)
float(1.3)
float(2.1)
float(2.5)
float(1)

Answer 2

希望这会帮助你，

正则表达式： \d+(?:\.\d+)?

1。 \d+这将匹配数字

2。 (?:\.\d+)?这可选择匹配小数部分

Try this code snippet here

<?php
ini_set('display_errors', 1);

$str_array=array(
"Up to $1.9 per Install in RU",
"1.3 per iOS Install in UAE and SA",
"$2.1 per iOS and Android Registration in US",
"Up to $2.5 per Android Install in 7 countries",
"Up to $1 per iOS Install in SA"
);
$result=array();
foreach($str_array as $string)
{
    preg_match_all('/[\d]+(?:\.[\d]+)?/',$string,$matches);
    $result[]=$matches[0][0];
}
print_r($result);

<强>输出：

Array
(
    [0] => 1.9
    [1] => 1.3
    [2] => 2.1
    [3] => 2.5
    [4] => 1
)

Answer 3

要仅选择行添加条件中的第一个数字

之前没有数字

^(?:[^\d]+)([+-]?(?:[0-9]*[.])?[0-9]+)

<强> demo and explanation

如何从字符串中获取数字/浮点数

3 个答案: