Question

我是Django和Python的新手，我用它来创建酒店预订网站。

我正在尝试取出与酒店相关的所有房间使用返回的对象我试图在返回的每个房间添加额外的属性。该属性将等于变量。

示例：

rooms = Room.object.filter(hotel=thehotel)
// for each room in rooms
Roomsavailable = Room.totalrooms
Roomsleft = RoomsAvailable - RoomsBooked

//attach roomsleft onto each room object
room.spaceleft = Roomsleft

任何帮助都会受到赞赏，希望我已经解释好了。

Answer 1

我似乎通过盯着邮政编码问题找到了自己的答案。

无论如何，对于可能偶然发现此事的人来说：

rooms = Room.objects.filter(hotel= thehotel) *// thehotel refers to an ID*

for room in rooms:
      room.spaceleft = 0   //setting the additional attribute
context = {'rooms':rooms}

*//passing the context to the template.*

return render(request, 'HotelApp/hoteldetails.html', context)

然后在模板中：

{% for room in rooms %}

<p> Rooms Left: {{room.spaceleft}} </p>   // using the additional attribute
{% endfor %}

如何将对象的附加属性

1 个答案: