Question

尝试创建对象的对象而不是我的代码正在创建对象数组。

我的程序代码

$output['result'] =[];
$query = "SELECT DISTINCT ti.`test_id`, ti.`name`, ti.`subject_id`, ti.`created_timestamp`, ti.`trainer_id`, ti.`class`, ti.`max_marks` , si.`name` as testname, ts.`validity` FROM `test_info` ti, `subject_info` si , `test_schools` ts WHERE ti.`subject_id` = si.`subject_id` AND ts.`test_id` = ti.`test_id` ";
$sth   = $dbh->prepare($query);
if (!$sth->execute()) {
    $dbh = null;
    throw new Exception(-1);
}
$rows = $sth->fetchALL(PDO::FETCH_ASSOC);
foreach($rows as $row){
    $keys = $row['test_id'];
    $output['result'][$keys] = [];  //Creating key 
    array_push($output['result'][$keys],$row); //Provide value to key 
}
echo json_encode($output);

这里我每次在循环中初始化一个数组，因为在JSON中将key作为test_id

$output['result'][$keys] = [];

这会导致对象数组，所以我如何转换为对象

节目输出

{  
   "result":{  
      "1":[  
         {  
            "test_id":"1",
            "name":"Physics",
            "subject_id":"2",
            "created_timestamp":"2017-03-23 17:55:51",
            "trainer_id":null,
            "class":"8",
            "max_marks":"10",
            "testname":"Physics",
            "validity":"2018-04-14"
         }
      ],
      "2":[  
         {  
            "test_id":"2",
            "name":"phys",
            "subject_id":"2",
            "created_timestamp":"2017-03-24 16:29:33",
            "trainer_id":null,
            "class":"8",
            "max_marks":"5",
            "testname":"Physics",
            "validity":"2017-03-25"
         }
      ]
   }
}

预期输出：

{  
   "result":{  
      "1":{  
         "test_id":"1",
         "name":"Physics",
         "subject_id":"2",
         "created_timestamp":"2017-03-23 17:55:51",
         "trainer_id":null,
         "class":"8",
         "max_marks":"10",
         "testname":"Physics",
         "validity":"2018-04-14"
      },
      "2":{  
         "test_id":"2",
         "name":"phys",
         "subject_id":"2",
         "created_timestamp":"2017-03-24 16:29:33",
         "trainer_id":null,
         "class":"8",
         "max_marks":"5",
         "testname":"Physics",
         "validity":"2017-03-25"
      }
   }
}

Answer 1

无需使用array_push，简单的foreach循环就足以完成它。在您的代码行$output['result'][$keys] = [];中，您创建了一个数组，然后您正在推进它，只有一个赋值可以帮助您实现预期的结果。

将其更改为：

foreach($rows as $row){
    $keys = $row['test_id'];
    $output['result'][$keys] = [];  //Creating key 
    array_push($output['result'][$keys],$row); //Provide value to key 
}

：此：

foreach ($rows as $row) { $keys = $row['test_id']; $output['result'][$keys] =$row ; //Creating key }

Try this code snippet here containing sample inputs

RestAPI用PHP设计 - 创建对象的对象而不是对象的数组

1 个答案: