Question

我在接受这项任务时遇到了麻烦（高中）。这是一个数字猜谜游戏，我已经把它的大部分都放下了，但他希望我们在控制台上放置一系列数字。输出示例如下：

输入下限：4

输入上限：10

等等，基本上选择您希望计算机选择的特定数字范围。我只能在一个范围内（1-1000）编码，因为我无法弄清楚如何做他想做的事情。这是我的代码：

import java.util.Scanner;


public class Game {
  public static void main(String[] args) {
        int randomNumber;
        randomNumber = (int) (Math.random() * 999 + 1);           
        Scanner keyboard = new Scanner(System.in);
        int guess;
 do {
            System.out.print("Enter a guess (1-1000): ");
            guess = keyboard.nextInt();

    if (guess == randomNumber)
  System.out.println("Your guess is correct. Congratulations!");
    else if (guess < randomNumber)
       System.out.println("Your guess is smaller than the secret number.");
  else if (guess > randomNumber)
 System.out.println("Your guess is greater than the secret number.");
        } while (guess != randomNumber);
  }

}

如果你尝试的话，反正也很难玩。我将不胜感激，谢谢！

Answer 1

对于范围内的随机数，您有两种选择：

Random rand = new Random();
// nextInt is normally exclusive of the top value,
// so add 1 to make it inclusive
int randomNum = rand.nextInt((max - min) + 1) + min;

或者在java 1.7或更高版本中：

int randomNum = ThreadLocalRandom.current().nextInt(min, max + 1);

Answer 2

如果您希望用户设置范围，您需要实现另一条线路，向用户询问范围

Scanner min= new Scanner(System.in);和Scanner max = new Scanner(System.in);

然后在您的代码randomNumber = (int) (Math.random() * 999 + 1);的这一行中，您现在可以使用用户输入random.nextInt(max - min + 1) + min设置您想要的范围

Answer 3

import java.util.Scanner;
public class Game {
public static void main(String[] args) {
  Scanner keyboard = new Scanner(System.in);
  System.out.println("enter minimum");
  int min= keyboard.nextInt();
  System.out.println("enter maximum");
  int max= keyboard.nextInt();
  int randomNumber= (int) (Math.random()* max + min);
  int guess;
  do {
     System.out.print("Enter a guess (1-1000): ");
     guess = keyboard.nextInt();

     if (guess == randomNumber)
        System.out.println("Your guess is correct. Congratulations!");
     else if (guess < randomNumber)
        System.out.println("Your guess is smaller than the secret number.");
     else if (guess > randomNumber)
        System.out.println("Your guess is greater than the secret number.");
   } while (guess != randomNumber);
  }
 }

数字猜测程序问题Java

3 个答案: