我正在尝试将两个列表(学生和课程)从Controller传递给jsp文件。它应该是两个dropbox,一个表单和一个提交按钮。现在我只能通过一个列表。想法是从一个Dropbox中选择学生,从另一个Dropbox中选择几个课程并提交注册。这是我的Controller,两个类:Student,Course和jsp文件。谢谢!
@Entity
@Table(name = "students")
public class Student {
@Id
@GeneratedValue
@Column(name = "STUDENT_ID")
private int studentId;
@Column(name = "name")
private String name;
@ManyToMany(cascade = CascadeType.ALL )
@JoinTable(name="STUDENT_COURSE", joinColumns={ @JoinColumn(name="STUDENT_ID")},
inverseJoinColumns = { @JoinColumn(name = "COURSE_ID") })
private Set<Course> courses = new HashSet<Course>();
public Student() {
}
public Student(String name) {
this.name = name;
}
public Student(String name, Set<Course> courses) {
this.name = name;
this.courses = courses;
}
public int getStudentId() {
return studentId;
}
public void setStudentId(int studentId) {
this.studentId = studentId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
'}';
}
}
@Entity
@Table(name = "courses")
public class Course {
@Id
@GeneratedValue
@Column(name = "COURSE_ID")
private int courseId;
@Column(name = "name")
private String courseName;
public Course() {
}
public Course(String courseName) {
this.courseName = courseName;
}
public String getCourseName() {
return courseName;
}
public void setCourseName(String courseName) {
this.courseName = courseName;
}
public int getCourseId() {
return courseId;
}
public void setCourseId(int courseId) {
this.courseId = courseId;
}
@Override
public String toString() {
return "Course{" +
"courseName='" + courseName + '\'' +
'}';
}
}
@Controller
public class RegistrationController {
@Autowired
private StudentService studentService;
@Autowired
private CourseService courseService;
@RequestMapping(value = "/register")
public String showRegister(Model model){
Student student = new Student();
Course course = new Course();
model.addAttribute("student", student);
model.addAttribute("course", course);
List<Student> students = studentService.showAllStudents();
model.addAttribute("students", students);
List<Course> courses = courseService.showAllCourses();
model.addAttribute("courses", courses);
return "registration";
} .
<%@ taglib prefix="form"
uri="http://www.springframework.org/tags/form"%>
<html>
<title>Spring MVC dropdown box</title>
<h2>Select student</h2>
<form:form method="POST" action ="register" commandName="student">
<table>
<tr>
<td>Please select:</td>
<td><form:select path="name" >
<form:option value="" label="student" />
<form:options items="${students}" />
</form:select>
</td>
<td><form:errors path="name" cssStyle="color: #ff0000;" /></td>
</tr>
<tr>
<td><input type="submit" name="submit" value="Submit"></td>
</tr>
</table>
</form:form>
。
答案 0 :(得分:0)
您可以为课程创建另一个<form:select
并删除commandName
,因为您可以将students
和courses
作为HTTP参数发送,然后可以从{{1控制器中的对象。
更新:最好创建一个简单的HTTPSerlvetRequest
而不是Spring <form>
,因为这只适用于将表单绑定到一个POJO时。