未经检查的调用map(Func1(<! - ?super T,?extends R - >)作为原始类型rx.Observable的成员

时间:2017-04-30 19:22:17

标签: java android rx-java

我编写了以下代码,将泛型集成到以下方法中。很明显,我是Generics的新手(之前没有创建过它们)。以下方法产生奇怪的警告

private static PublishSubject mPublishSubject;

public <T> void register(final Class<T> type, Action1<T> observerAction) {
        mPublishSubject.filter(new Func1<T, Boolean>() {
            @Override
            public Boolean call(T o){
                Timber.e("Filter(): object type: %s typeClass is: %s", o.getClass(), type);
                if(o.getClass().equals(type)) {
                    Timber.e("Filer() return true");
                    return true;
                }
                Timber.e("Filer() return false");
                return false;
            }
        }).map(new Func1<T, T>() {
            @Override
            public T call(@NonNull T o) {
                Timber.e("Map(): object received from filter: %s", o);
                return o;
            }
        }).subscribe(observerAction);
    }

以下是我收到的警告。

Unchecked call to map(Func1(<? super T, ? extends R>) as a member of raw type rx.Observable.

Unchecked call to subscribe(Action1(<? super T>) as a member of raw type rxObservable.

这些警告意味着什么?我在哪里弄错了?

0 个答案:

没有答案