在Java中

时间:2017-04-30 17:01:32

标签: java arrays 2d transpose

嘿我试图转置用户输入的行/列的二维数组。我在这个网站上四处看看,我看到的所有建议都是方阵(2x2,3x3等等)

这是我到目前为止所拥有的

import java.util.Scanner;

public class ArrayTranspose {

public static void main(String[] args) {
    Scanner kb = new Scanner(System.in);

    System.out.print("Input the number of rows (must be between 2 and 5): ");
    int rows = kb.nextInt();
    if ((rows < 2) && (rows > 5)) {
        System.out.println("Error: range must be between 2-5");
        rows = -1;
    }
    System.out.print("Input the number of columns (must be between 2 and 5): ");
    int cols = kb.nextInt();
    if ((cols < 2) && (cols > 5)) {
        System.out.println("Error: range must be between 2-5");
        cols = -1;
    }

    int myArray[][] = new int[rows][cols];

    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            System.out.println("Enter a data value for (" + (i + 1) + ", " + (j + 1) + "): ");
            int value = kb.nextInt();
            myArray[i][j] = value;
        }
    }
    printArray(myArray);
    System.out.println();
    int newArray[][] = transpose(myArray);
    printNewArray(newArray);
}

public static void printArray(int myArray[][]) {
    int dim1 = myArray.length; // Gets the number of rows
    int dim2 = myArray[0].length; // Gets the number of columns

    for (int i = 0; i < dim1; i++) {
        for (int j = 0; j < dim2; j++) {
            System.out.printf("%4d", myArray[i][j]);
        }
        System.out.println();
    }
}

public static int[][] transpose(int myArray[][]) {
    int newArray[][] = new int[myArray[0].length][myArray.length];

    for (int i = 0; i < myArray.length; i++) {
        for (int j = 0; j < i; j++) {
            // swap element[i,j] and element[j,i]
            int temp = myArray[i][j];
            newArray[i][j] = temp;
        }
    }
    return newArray;
}

public static void printNewArray(int myArray[][]) {
    int dim1 = myArray.length; // Gets the number of rows
    int dim2 = myArray[0].length; // Gets the number of columns

    for (int i = 0; i < dim1; i++) {
        for (int j = 0; j < dim2; j++) {
            System.out.printf("%4d", myArray[i][j]);
        }
        System.out.println();
    }
}
}

当我运行程序时,我得到这样的东西:

输入行数(必须介于2和5之间):2

输入列数(必须介于2和5之间):3

输入(1,1)的数据值:

11

输入(1,2)的数据值:

12

输入(1,3)的数据值:

13

输入(2,1)的数据值:

21

输入(2,2)的数据值:

22

输入(2,3)的数据值:

23

11 12 13

21 22 23

0 0

21 0

0 0

所以看起来一切进展顺利(它知道转置数组的新维度)但是转置数组中的数据值不会占用原始数组中的所有数字。

2 个答案:

答案 0 :(得分:0)

    public static int[][] transpose(int myArray[][]) {
    int newArray[][] = new int[myArray[0].length][myArray.length];

    for (int i = 0; i < myArray[0].length; i++) {
        for (int j = 0; j < myArray.length; j++) {
            int temp = myArray[j][i];
            newArray[i][j] = temp;
        }
    }
    return newArray;
}

希望这有助于:)

答案 1 :(得分:0)

我只在这个地方做了一点简单:

public static int[][] transpose(int myArray[][]) {
    int newArray[][] = new int[myArray[0].length][myArray.length];

    for (int i = 0; i < newArray.length; i++) {
        for (int j = 0; j < newArray[i].length; j++) {
            newArray[i][j] = myArray[j][i];
        }
    }
    return newArray;
}