Question

我设法在对象数组中找到min和max，但同时我必须包含其他变量。我有额外的special_min_price和special_max_price，如何在reduce方法中包含它们？

const price = [
{min_price:100, max_price:200},
{min_price:70, max_price:200},
{min_price:50, max_price:100},
{min_price:100, max_price:400},
{min_price:120, max_price:600},
],
special_min_price = 40,
special_max_price = 800;

let x = _.reduce(price, function(a, b) {
            a.min_price = Math.min(a.min_price, b.min_price);
            a.max_price = Math.max(a.max_price, b.max_price);
            return a
        });

Answer 1

我认为你希望特价能成为减价的一部分。如果是这种情况，那么您可以尝试在缩减之前添加一个步骤，然后添加到价格列表中。我想它看起来像这样：

const price = [
{min_price:100, max_price:200},
{min_price:70, max_price:200},
{min_price:50, max_price:100},
{min_price:100, max_price:400},
{min_price:120, max_price:600},
],
special_min_price = 40,
special_max_price = 800;

let x = _.chain(price)
         .concat({min_price:special_min_price,
             max_price:special_max_price})
         .reduce(function(a, b) {
             a.min_price = Math.min(a.min_price, b.min_price);
             a.max_price = Math.max(a.max_price, b.max_price);
             return a
         })
         .value();

使用reduce查找min和max但有额外条件

1 个答案: