Question

我正在尝试设计一个递归函数，它接受来自用户的两个参数并将它们放入参数x和y中。该函数应返回x乘以y的值。我的代码无法正确执行，因为我试图在return语句中传递x和y变量，但我无法弄清楚我做错了什么。

def main():

    #get the user to input a two integers and defines them as x and y
    x = int(input("Please enter a positive integer: "))
    y = int(input("Please enter a second positive integer: "))

    #make sure the integer selection falls within the parameters
    if (y == 0):
        return 0
    return x+(x,y-1)

#call the main function
main()

我的追溯说：

返回x +（x，y-1）TypeError：+：＆＃39; int＆＃39;不支持的操作数类型和＆＃39;元组＆＃39;

Answer 1

`您可以尝试这些方法：

def main():

    #get the user to input a two integers and defines them as x and y
    x = int(input("Please enter a positive integer: "))
    y = int(input("Please enter a second positive integer: "))

    print recursive_mult(x, y)

def recursive_mult(x, y):
    if y == 0:
        return 0
    return x + recursive_mult(x, y - 1)

您看到的错误是由于尝试向x的元组添加int值(x, y - 1)引起的，而您可能希望对某些函数进行递归调用这些值并将结果添加到x。

Answer 2

def main():

    #get the user to input a two integers and defines them as x and y
    x = int(input("Please enter a positive integer: "))
    y = int(input("Please enter a second positive integer: "))

    print( mul(x, y) )

def mul(x, y):
    if y==0: return 0
    return x + mul(x, y-1)

我的python函数有什么问题？

2 个答案: